[x y​]+[w z​]=[x+2w y−2z​]α[x y​]=[αx αy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? [xy​]+[wz​]=[x+2wy−2z​]α[xy​]=[αxαy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? a. No, because though the Additive Inverse axiom is satisfied, the Commutative is not satisfied b. Yes, because all 10 vector space axioms are satisfied c. No, because the One axiom is not satisfied, though the Zero and Additive clousre are satisfied d. No, because neither the Zero axiom nor the Additive Inverse axiom is satisfied e. No, because the Additive Inverse axiom is not satisfied, though the Commutative is satisfied f. No, because the Additive Closure axiom is not satisfied, though the Scalar multiplication is satisfied g. No, because though the Additive Closure axiom is satisfied, the Scalar multiplication is not satisfied h. No, because neither the Zero axiom nor the One axiom is satisfied

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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[x y​]+[w z​]=[x+2w y−2z​]α[x y​]=[αx αy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? [xy​]+[wz​]=[x+2wy−2z​]α[xy​]=[αxαy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? a. No, because though the Additive Inverse axiom is satisfied, the Commutative is not satisfied b. Yes, because all 10 vector space axioms are satisfied c. No, because the One axiom is not satisfied, though the Zero and Additive clousre are satisfied d. No, because neither the Zero axiom nor the Additive Inverse axiom is satisfied e. No, because the Additive Inverse axiom is not satisfied, though the Commutative is satisfied f. No, because the Additive Closure axiom is not satisfied, though the Scalar multiplication is satisfied g. No, because though the Additive Closure axiom is satisfied, the Scalar multiplication is not satisfied h. No, because neither the Zero axiom nor the One axiom is satisfied

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