x = x, + Va! + }a,r? v = vồ, + 2a,(x– x,) v =v, + 2a,(y – y.) 2 Problem Every year at UC-Berkeley students engage in an event called the “TV-Toss". Men and women test their strength by hurling their TV sets horizontally over a very high cliff. When Rachel, shown at left, heaves her TV at t=0s it has a horizontal velocity of 1.5 m/s when it leaves her hand. After 2 s it is still in the air (point B in the diagram.) Note: use a;-10 m/s² to simplify the calculations and ignore air friction. OB

x = x, + Va! + }a,r? v = vồ, + 2a,(x– x,) v =v, + 2a,(y – y.) 2 Problem Every year at UC-Berkeley students engage in an event called the “TV-Toss". Men and women test their strength by hurling their TV sets horizontally over a very high cliff. When Rachel, shown at left, heaves her TV at t=0s it has a horizontal velocity of 1.5 m/s when it leaves her hand. After 2 s it is still in the air (point B in the diagram.) Note: use a;-10 m/s² to simplify the calculations and ignore air friction. OB

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

How to solve for #3-#7 using the given equations and explain what they mean if possible. Thank you!

For #3 I got D and #4 I got B, not sure I am correct with those two :(

This problem should look familiar, as it similar to one you did for homework. You may need the following
relationships derived in chapter 2; they are the kinematic equations for constant acceleration.
v, = Vo, +a,t
v, = Voy +a,1
x = x, + Va! + £ar°
v = v, + 2a,(x- x,)
y= y, + Va,1 +a,r
v = v, + 2a, (y - y,)
+ Vay
V, + Vo..
2
Problem
OB Every year at UC-Berkeley students engage in an event called the "TV-Toss". Men and
women test their strength by hurling their TV sets horizontally over a very high cliff.
When Rachel, shown at left, heaves her TV at t=0s it has a horizontal velocity of 1.5
m/s when it leaves her hand. After 2 s it is still in the air (point B in the diagram.) Note:
use a-10 m/s' to simplify the calculations and ignore air friction.
1. Which of the following arrows best
indicates the direction of the TV's
acceleration at point B?
What horizontal distance has the TV traversed
6.
in the first two seconds?
А. 3 m
В. 20 m
С. 20.2 m
D. 23 m
A.
В.
c.
D. I
7. What angle below the horizontal is the TV
moving at point B?
А. 0°
В. 4.3°
С. 60°
D. 85.7°
E. 90°
2. Which of the following arrows best
indicates the direction of the TV's velocity
at point B?
A.
В.
с.
D. I
3. At =2 s, what is the TV's vertical velocity?
A. O m/s
B. 1.5 m/s
C. 20 m/s
D. 21.5m/s
4. Att=2 s, what is the TV's horizontal velocity?
A. O m/s
B. 1.5 m/s
С. 20 m/s
D. 21.5m/s
5. What vertical distance has the TV fallen in the
first two seconds?
А. 3 m
В. 20 m
С. 20.2 m
D. 23 m

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