A spherical capacrtor consists of a spherical conducting shell of radius b and - Q that is concentric with a Smaller conducting sphere of radius a charge and charge + Q. Shorw thet er its capacitance is C= ab KeCb-a) B) Shonw that as b approaches infinity, the capacitance approaches the value a potential difference is propotional to the charge Q on the iapacitor Ke AV A First find the E- feid of the ioner sehere:

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Good evening! I am curious if I am just supposed to take the limit of what I got in part a) as b approaches infinity to solve for part b. Am I overthinking this? Is there an easier way or am I on the right path with my assumption? Thank you!!!!
II
F9
CHAPTER 20 (36)
A spherical capacrtor consists of a spherical conducting shell of radius b and
charge
Q and charge + Q.
A) Show that ien its capacitance is
delete
Q that is concentric with a smaller conducting sphere of radius a
C = ab
Ke(b-a)
enter
B) Shorv that as b approaches infinity, the capacitance approaches the value
a
Ke
return
potential difference is propotional
to the charge Q on the capacitor
shift
control
C= Q
AV
KANDT First, find the E-field of the inner sphere:
ent.
-uSE THE RELATION SHP THAT E= v E•r(ifGis constant)
E,= ke Q
(distene
It is NoT in this case so we can use
dv= Edr where dvis potential change
between the inner and outer sphere.
KeQ are constants
traveled)
ROL
AV = YeS dv= -S ke Q dr
V= Sav= -SEdr
a.
-keafr"dr = -ke Q/
The 6) is becauuse as the radius
ineveazes, the poten tial decreases.
(AS E gets bigger, V gets snaller)
use a and b as bound s, use
bigger (b) as bottom bound to get
a'+V since the Vrill bet when
we Move from a farther
get closer.
Ke Q
- ke Q_ Ke Q ca)
6 (b) a
TUAL
b (a)
bkeQ-keaQ
KeQ(b-a)
place
and
ab
ab
put thisinto (= Q
(=Q
C= & ab
Ke&(6-a) TkeCb-a) =C
Ke Q(b-a)
ab
%3D
ab
Transcribed Image Text:II F9 CHAPTER 20 (36) A spherical capacrtor consists of a spherical conducting shell of radius b and charge Q and charge + Q. A) Show that ien its capacitance is delete Q that is concentric with a smaller conducting sphere of radius a C = ab Ke(b-a) enter B) Shorv that as b approaches infinity, the capacitance approaches the value a Ke return potential difference is propotional to the charge Q on the capacitor shift control C= Q AV KANDT First, find the E-field of the inner sphere: ent. -uSE THE RELATION SHP THAT E= v E•r(ifGis constant) E,= ke Q (distene It is NoT in this case so we can use dv= Edr where dvis potential change between the inner and outer sphere. KeQ are constants traveled) ROL AV = YeS dv= -S ke Q dr V= Sav= -SEdr a. -keafr"dr = -ke Q/ The 6) is becauuse as the radius ineveazes, the poten tial decreases. (AS E gets bigger, V gets snaller) use a and b as bound s, use bigger (b) as bottom bound to get a'+V since the Vrill bet when we Move from a farther get closer. Ke Q - ke Q_ Ke Q ca) 6 (b) a TUAL b (a) bkeQ-keaQ KeQ(b-a) place and ab ab put thisinto (= Q (=Q C= & ab Ke&(6-a) TkeCb-a) =C Ke Q(b-a) ab %3D ab
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We have to find out value of capacitance when b approach to infinity.

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