X Graph T² (s²) (on vertical axis) vs. M (kg) (horizontal axis). Perform a best fit line, read from your graph the intercept. 5. By squaring eq. (3) you get: (4) as the slope and -m, as 477² 3k 7² = 4² (M + ¹m₂) k 47² 6.) Equation (4) states that T2 is proportional to M with the intercept. k 7. From your graph, read where the best-fit line intersects Y-axis, this value is your intercept. Intercept= ms (measured value)=_ 0.19 15/5² (unit?) and solve for the ms 8. Equate the value of the intercept determined in Step 7 to value of the ms. In this evaluation consider the value of k obtained from previous graph. Show your calculation to get credit! 47² 3k (unit?) (calculated from intercept)

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Chapter1: Units, Trigonometry. And Vectors
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Hello, can you please help me do parts 5, 6 and 8. I also attached a pic of the graph
X. Calculate average (mean) At (s) of the three readings.
2. Get the period T=4t (s)/10 (because you timed 10 periods!).
3. Calculate period squared T² (s²) by squaring the period T.
T (s)
M (g)
M (kg) At₁ (s)
At₂ (s)
Δt (s)
At3 (s)
100
150
200
250
0.05
0.1
0.15
0.2
0.25
X
6.37
8.0
9.80
11-01
11-22
8.10
9.76
11.24
12.46
T² =
6-31
8.14
9.91
11.19
11.16
6-28
ms (measured value)=_
8.13
Q.8
11-15
11.6
0.62
0.81
0.98
1.11
1.16
477²
k
T² (S²)
0.39
1.34
Y
A. Graph T2 (s²) (on vertical axis) vs. M (kg) (horizontal axis). Perform a best fit line,
read from your graph the intercept.
5. By squaring eq. (3) you get:
0.65
0.96
1.23
47² (M + ² ms)
k
6.) Equation (4) states that T² is proportional to M with
the intercept.
7. From your graph, read where the best-fit line intersects Y-axis, this value is your
intercept.
Intercept=
(4)
m, as
as the slope and
47²
3k
125 15²
0.19
(unit?)
47²
3k
ms and solve for the
8. Equate the value of the intercept determined in Step 7 to
value of the ms. In this evaluation consider the value of k obtained from previous
graph. Show your calculation to get credit!
(unit?) (calculated from intercept)
Transcribed Image Text:X. Calculate average (mean) At (s) of the three readings. 2. Get the period T=4t (s)/10 (because you timed 10 periods!). 3. Calculate period squared T² (s²) by squaring the period T. T (s) M (g) M (kg) At₁ (s) At₂ (s) Δt (s) At3 (s) 100 150 200 250 0.05 0.1 0.15 0.2 0.25 X 6.37 8.0 9.80 11-01 11-22 8.10 9.76 11.24 12.46 T² = 6-31 8.14 9.91 11.19 11.16 6-28 ms (measured value)=_ 8.13 Q.8 11-15 11.6 0.62 0.81 0.98 1.11 1.16 477² k T² (S²) 0.39 1.34 Y A. Graph T2 (s²) (on vertical axis) vs. M (kg) (horizontal axis). Perform a best fit line, read from your graph the intercept. 5. By squaring eq. (3) you get: 0.65 0.96 1.23 47² (M + ² ms) k 6.) Equation (4) states that T² is proportional to M with the intercept. 7. From your graph, read where the best-fit line intersects Y-axis, this value is your intercept. Intercept= (4) m, as as the slope and 47² 3k 125 15² 0.19 (unit?) 47² 3k ms and solve for the 8. Equate the value of the intercept determined in Step 7 to value of the ms. In this evaluation consider the value of k obtained from previous graph. Show your calculation to get credit! (unit?) (calculated from intercept)
Slope
1.5
2
1-23
1
0-96
0.65
0-S
P(5²)
039
0-2
D-2
0-₁1
520
6-10
0.15
Free Multi-Width Graph Paper from http://incomp
10.20
0.25
igraphpaper multwidth
0.30
5⁰ M (kg)
Transcribed Image Text:Slope 1.5 2 1-23 1 0-96 0.65 0-S P(5²) 039 0-2 D-2 0-₁1 520 6-10 0.15 Free Multi-Width Graph Paper from http://incomp 10.20 0.25 igraphpaper multwidth 0.30 5⁰ M (kg)
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