x² - 1 Consider the following function: f(x)= Find the equation for Зx2 — 3х — 6 each horizontal asymptote and each vertical asymptote. Justify your answer. Find the x- and y-intercepts. Find the domain.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

Consider the following function:

\[ f(x) = \frac{x^2 - 1}{3x^2 - 3x - 6} \]

1. **Find the equation for each horizontal asymptote and each vertical asymptote. Justify your answer.**
2. **Find the \( x \)- and \( y \)-intercepts.**
3. **Find the domain.**

### Instructions for Analysis

#### 1. Asymptote Analysis
- **Horizontal Asymptote:** To determine the horizontal asymptote, compare the degrees of the numerator and the denominator of the function \( f(x) \).
- **Vertical Asymptote:** To find the vertical asymptote, set the denominator equal to zero and solve for \( x \).

#### 2. Intercept Analysis
- **\( x \)-intercepts:** Set the numerator equal to zero and solve for \( x \).
- **\( y \)-intercepts:** Evaluate \( f(0) \).

#### 3. Domain Analysis
- Identify the values of \( x \) for which the function \( f(x) \) is undefined (i.e., where the denominator is zero).

### Detailed Steps and Solutions

**Horizontal Asymptote:**

- The degrees of the numerator and the denominator are both 2. The horizontal asymptote is found by taking the leading coefficients of \( x^2 \) from both the numerator and the denominator. Thus, the horizontal asymptote is:

\[ y = \frac{1}{3}. \]

**Vertical Asymptote:**

- Set the denominator equal to zero and solve for \( x \):

\[ 3x^2 - 3x - 6 = 0. \]

- Factor the quadratic equation:

\[ 3(x^2 - x - 2) = 0 \implies 3(x - 2)(x + 1) = 0. \]

- The solutions are:

\[ x = 2 \quad \text{and} \quad x = -1. \]

Thus, the vertical asymptotes are:

\[ x = 2 \quad \text{and} \quad x = -1. \]

**\( x \)-intercepts:**

- Set the numerator equal to zero and solve for \( x \):

\[ x^2 - 1 = 0 \
Transcribed Image Text:### Problem Statement Consider the following function: \[ f(x) = \frac{x^2 - 1}{3x^2 - 3x - 6} \] 1. **Find the equation for each horizontal asymptote and each vertical asymptote. Justify your answer.** 2. **Find the \( x \)- and \( y \)-intercepts.** 3. **Find the domain.** ### Instructions for Analysis #### 1. Asymptote Analysis - **Horizontal Asymptote:** To determine the horizontal asymptote, compare the degrees of the numerator and the denominator of the function \( f(x) \). - **Vertical Asymptote:** To find the vertical asymptote, set the denominator equal to zero and solve for \( x \). #### 2. Intercept Analysis - **\( x \)-intercepts:** Set the numerator equal to zero and solve for \( x \). - **\( y \)-intercepts:** Evaluate \( f(0) \). #### 3. Domain Analysis - Identify the values of \( x \) for which the function \( f(x) \) is undefined (i.e., where the denominator is zero). ### Detailed Steps and Solutions **Horizontal Asymptote:** - The degrees of the numerator and the denominator are both 2. The horizontal asymptote is found by taking the leading coefficients of \( x^2 \) from both the numerator and the denominator. Thus, the horizontal asymptote is: \[ y = \frac{1}{3}. \] **Vertical Asymptote:** - Set the denominator equal to zero and solve for \( x \): \[ 3x^2 - 3x - 6 = 0. \] - Factor the quadratic equation: \[ 3(x^2 - x - 2) = 0 \implies 3(x - 2)(x + 1) = 0. \] - The solutions are: \[ x = 2 \quad \text{and} \quad x = -1. \] Thus, the vertical asymptotes are: \[ x = 2 \quad \text{and} \quad x = -1. \] **\( x \)-intercepts:** - Set the numerator equal to zero and solve for \( x \): \[ x^2 - 1 = 0 \
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