If f(x) = 3x2x+5, find the following. f(1) = 7 f(-1) = 9 f(a) = 3a² a +5 f(-a) = f(a + 1) = 2 3a² + a +5 3a² + 5a+7 2f(a) = f(2a) = f(a²) [f(a)]² = = f(a + h) =
If f(x) = 3x2x+5, find the following. f(1) = 7 f(-1) = 9 f(a) = 3a² a +5 f(-a) = f(a + 1) = 2 3a² + a +5 3a² + 5a+7 2f(a) = f(2a) = f(a²) [f(a)]² = = f(a + h) =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![If f(x)
=
3x2x+5, find the following.
f(1) =
7
f(-1) =
9
f(a) =
3a²
a +5
f(-a)
=
f(a + 1) =
2
3a²
+ a +5
3a² + 5a+7
2f(a) =
f(2a) =
f(a²)
[f(a)]²
=
=
f(a + h) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F77dede99-e262-49a4-b559-7f97b49ff6c0%2F8244a178-5a50-4478-8a54-16b055269acd%2Fq5ntidr_processed.png&w=3840&q=75)
Transcribed Image Text:If f(x)
=
3x2x+5, find the following.
f(1) =
7
f(-1) =
9
f(a) =
3a²
a +5
f(-a)
=
f(a + 1) =
2
3a²
+ a +5
3a² + 5a+7
2f(a) =
f(2a) =
f(a²)
[f(a)]²
=
=
f(a + h) =
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