wwwwwwww wwwwwwwww If the progeny of the cross aaBB x AAbb is testcrossed, and the following genotypes are observed among the progeny of the testcross, what is the frequency of recombination between these loci? AaBb 135 wwwwwwww Aabb 430 www aaBb 390 wwwwwwww aabb 120 wwwwww

wwwwwwww wwwwwwwww If the progeny of the cross aaBB x AAbb is testcrossed, and the following genotypes are observed among the progeny of the testcross, what is the frequency of recombination between these loci? AaBb 135 wwwwwwww Aabb 430 www aaBb 390 wwwwwwww aabb 120 wwwwww

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

See similar textbooks

Similar questions

Define the pedigree symbol(s) associated with each of the following individuals. Please be as specific as possible. Be sure to indicate WHOSE pedigree symbols you are defining. (i) II-1 and II-3 (ii) II-5 (iii) II-9-10 (iv) II-11 (v) IV-14 and IV-15 (vi) IV-18
For each Down syndrome fact, click to specify if the fact is true about Trisomy 21, translocation, or mosaic Down syndrome. Some facts may apply to more than one type.
Please explain how I can solve this. Thank you You wanted to draw a linkage map for three genes in the fruit fly (A, B, C) that you suspect are linked. You have done a three-point testcross and found that out of the 1500 progeny in the cross, 612 are a · b · c, 603 are A · B · C, 93 are a · B · C, 85 are A · b · c, 53 are a · b · C, 47 are A · B · c, 5 are A · b · C, and 2 are a · B · c. From this data, you can deduce that the genes are linked and the distance between B and C is:
GsnKivd010j2gIRWLIZOMZZ-VibKYvBbo61ylATAQ/viewform RECOMBINATION". For numbers 7-35, reler to the given data below. Glven the following testcross data for com In whlch the genes for fine stripe (f), bronze gleurone (bz) and knotted leaf (Kn) are involved: + = wild type f fine stripe +=wild type bz = bronze gleurone +=wild type Kn knotted leaf %3D Genotype Ko f Number 451 Ko 134 97 436 bz bz bz Ko 18 119 f 24 Kn f bz 86 Total: Your answer 7-8. What would be the recombination frequency or the frequency of the recombinant type between +/Kn and +/f genes? Oa. 16% O b. 16 map units + + + + +
This is what I was tested on last week. All the information is already in the question. The professor gave me no other information.
Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000 9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…
I II III II-1 11-2 Aa 1-1 11-3 Aa 1-2 II-4 III-1 Example: Given the pedigree above, what is the probability that the granddaughter (III-1) will be heterozygous? In order to determine the probability that III-1 is heterozygous, we need to determine the probability of the possible genotypes for her mother (II-2). Because the grandparents are both heterozygous, we would expect the following genotypic ratios in their offspring: ¼ AA, ½ Aa, and 14 aa. However, we have to use all possible information, and the circle representing III-1 is not shaded in, so she cannot be aa. Therefore, we eliminate the probability that II-2 is aa, and the final probability for II-2 is 1/3 AA and 2/3 Aa. We assume II-1 is AA because he is marrying into the family and we assume everyone marrying into a family is homozygous wild-type, unless proven otherwise. If II-2 is AA, and we assume II-1 is AA, then there is no chance that their daughter (III-1) is Aa If II-2 is Aa, and we assume II-1 is AA, then there is a…
Please help with parts a and b please. a) You are a farmer taking your squash to the farmer’s market. Green squash happens to be very popular with your customers and can be sold at a higher price than white or yellow squash. Which of the following squash plant crosses will give you a higher number of green squash to bring to the market? Show your work 1. AaBb (white) x Aabb (yellow) or 2. aaBb (white) x Aabb (yellow) b) What type of epistasis does this squash coloration likely demonstrate and why?
Please answer all parts along with the reason. I'll definitely give a like. Thank you in advance! 1A) From the cross Ab/aB x ab/ab, what is the recombination frequency if the progeny numbers are 17 AB/ab, 72 Ab/ab, 68 aB/ab, and 21 ab/ab? 1B)In human gene mapping, a LOD score is calculated to see if a gene causing a rare disease is linked to a known SNP. The LOD score is -4. This means that 1C) A three-point testcross is used to determine the order of three linked genes. The following crossover progeny result: single crossovers, double crossovers, and no crossovers. To determine the order, the no-crossover progeny must be compared to what other class of progeny?
please help with the drawing linkage meisosis question, as well, as the one below it with the punnett square that isn't completed.
Locus A has two alleles (A and a) while locus B has two alleles (B and b). The recombination frequency between locus A and locus B is 17%. A F1 heterozygote in trans-configuration is mated with an aabb individual. What are the expected phenotypic percentages in the resulting progeny? Round your percentages to the nearest tenths and in the following format, replacing the "0.0" with your percentages:
Please indicate the recominant individiual in the given pedigree. Please explain your answer. AB CC BC AD AB CD AC CD AC DD AC BC AC BD AD CD BB вс BD