ww im R1 V I sine î sine In the above circuit, let R1 = 8 ohm, reactance of L1 be j12 ohm. RMS value of the voltage source is 180 volt at phase angle 0 degree. The voltage source supplied 2.5 KW and 0.4 kVaR power. Determine the current source value in complex phasor form. Re()= ampere Im(1) = ampere
ww im R1 V I sine î sine In the above circuit, let R1 = 8 ohm, reactance of L1 be j12 ohm. RMS value of the voltage source is 180 volt at phase angle 0 degree. The voltage source supplied 2.5 KW and 0.4 kVaR power. Determine the current source value in complex phasor form. Re()= ampere Im(1) = ampere
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
![ww
R1
I
V
sine
sine
In the above circuit, let R1 = 8 ohm, reactance of L1 be j12 ohm. RMS value of the voltage source is 180 volt at phase angle 0 degree. The voltage source supplied 2.5 KW and 0.4 kVaR power.
Determine the current source value in complex phasor form.
Re()=
ampere
Im(1)
=
ampere
ell
L1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6909209-2086-4a3d-aec9-bf6e52ddf5c5%2F4fa99883-0217-4e85-83d9-df1d96590d82%2Fzu0cc2l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ww
R1
I
V
sine
sine
In the above circuit, let R1 = 8 ohm, reactance of L1 be j12 ohm. RMS value of the voltage source is 180 volt at phase angle 0 degree. The voltage source supplied 2.5 KW and 0.4 kVaR power.
Determine the current source value in complex phasor form.
Re()=
ampere
Im(1)
=
ampere
ell
L1
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