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Write TRUE if the underlined word/phrase makes the statement correct. Otherwise, write the correct WORD/PHRASE that will make the statement true. 1. Aldehydes and ketones generally react in a mechanism known as nucleophilic substitution reaction at the carboxylic oxygen. 2. 1-cyclopentylethan-1-one will test positive in baeyer's test and will test positive in tollen's test. 3. Gulose and idose produce the same osazones. 4. Seliwanoff's test can be used to differentiate sorbose and talose 5. Ribose is a C2 epimer of arabinose and a C4 epimer of xylose. 6. In the test for benzoic acid, boiling-off excess FeCl3 prevents the formation of Fe(OH)3 precipitate. 7. The vapor produced from the base-promoted hydrolysis of propanamide turned the blue litmus paper to red. 8. Anhydrous Na₂SO4 was added in the obtained organic layer to remove excess water. 9. In the synthesis of esters, using acyl chlorides as starting materials instead of carboxylic acids could decrease the product yield. 10. The reaction between N-methylaminobenzoic acid and benzenesulfonyl chloride will produce a sulfonamide that is soluble in excess NaOH. 11. Performing Liebermann's nitroso test on pentanamine will result to effervescence. 12. Reacting a tertiary amine with BSC produces a sulfonamide that is insoluble in NaOH.

Write TRUE if the underlined word/phrase makes the statement correct. Otherwise, write the correct WORD/PHRASE that will make the statement true. 1. Aldehydes and ketones generally react in a mechanism known as nucleophilic substitution reaction at the carboxylic oxygen. 2. 1-cyclopentylethan-1-one will test positive in baeyer's test and will test positive in tollen's test. 3. Gulose and idose produce the same osazones. 4. Seliwanoff's test can be used to differentiate sorbose and talose 5. Ribose is a C2 epimer of arabinose and a C4 epimer of xylose. 6. In the test for benzoic acid, boiling-off excess FeCl3 prevents the formation of Fe(OH)3 precipitate. 7. The vapor produced from the base-promoted hydrolysis of propanamide turned the blue litmus paper to red. 8. Anhydrous Na₂SO4 was added in the obtained organic layer to remove excess water. 9. In the synthesis of esters, using acyl chlorides as starting materials instead of carboxylic acids could decrease the product yield. 10. The reaction between N-methylaminobenzoic acid and benzenesulfonyl chloride will produce a sulfonamide that is soluble in excess NaOH. 11. Performing Liebermann's nitroso test on pentanamine will result to effervescence. 12. Reacting a tertiary amine with BSC produces a sulfonamide that is insoluble in NaOH.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Write TRUE if the underlined word/phrase makes the statement correct. Otherwise, write the correct WORD/PHRASE that will make the statement true. 1. Aldehydes and ketones generally react in a mechanism known as nucleophilic substitution reaction at the carboxylic oxygen. 2. 1-cyclopentylethan-1-one will test positive in baeyer's test and will test positive in tollen's test. 3. Gulose and idose produce the same osazones. 4. Seliwanoff's test can be used to differentiate sorbose and talose 5. Ribose is a C2 epimer of arabinose and a C4 epimer of xylose. 6. In the test for benzoic acid, boiling-off excess FeCl3 prevents the formation of Fe(OH)3 precipitate. 7. The vapor produced from the base-promoted hydrolysis of propanamide turned the blue litmus paper to red. 8. Anhydrous Na₂SO4 was added in the obtained organic layer to remove excess water. 9. In the synthesis of esters, using acyl chlorides as starting materials instead of carboxylic acids could decrease the product yield. 10. The reaction between N-methylaminobenzoic acid and benzenesulfonyl chloride will produce a sulfonamide that is soluble in excess NaOH. 11. Performing Liebermann's nitroso test on pentanamine will result to effervescence. 12. Reacting a tertiary amine with BSC produces a sulfonamide that is insoluble in NaOH. 13. The solution containing B-naphthol was placed in acidic solution to enhance the electron donating capability of the hydroxyl group by converting it into an oxide group. 14. If the preparation of the phenyldiazonium ion was done at low pH, the phenyldiazonium would also form another species, a N-nitroso compound which is incapable of coupling.
Transcribed Image Text:Write TRUE if the underlined word/phrase makes the statement correct. Otherwise, write the correct WORD/PHRASE that will make the statement true. 1. Aldehydes and ketones generally react in a mechanism known as nucleophilic substitution reaction at the carboxylic oxygen. 2. 1-cyclopentylethan-1-one will test positive in baeyer's test and will test positive in tollen's test. 3. Gulose and idose produce the same osazones. 4. Seliwanoff's test can be used to differentiate sorbose and talose 5. Ribose is a C2 epimer of arabinose and a C4 epimer of xylose. 6. In the test for benzoic acid, boiling-off excess FeCl3 prevents the formation of Fe(OH)3 precipitate. 7. The vapor produced from the base-promoted hydrolysis of propanamide turned the blue litmus paper to red. 8. Anhydrous Na₂SO4 was added in the obtained organic layer to remove excess water. 9. In the synthesis of esters, using acyl chlorides as starting materials instead of carboxylic acids could decrease the product yield. 10. The reaction between N-methylaminobenzoic acid and benzenesulfonyl chloride will produce a sulfonamide that is soluble in excess NaOH. 11. Performing Liebermann's nitroso test on pentanamine will result to effervescence. 12. Reacting a tertiary amine with BSC produces a sulfonamide that is insoluble in NaOH. 13. The solution containing B-naphthol was placed in acidic solution to enhance the electron donating capability of the hydroxyl group by converting it into an oxide group. 14. If the preparation of the phenyldiazonium ion was done at low pH, the phenyldiazonium would also form another species, a N-nitroso compound which is incapable of coupling.
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