Write the sequence of commands required to update the CHAR_FLT_CHG_HR attribute values in the CHARTER table.
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Write the sequence of commands required to update the CHAR_FLT_CHG_HR attribute values in the CHARTER table.
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- The option for referential integrity between the Owner table and the Pet table is restrict. An attempt is made to delete the row for owner number 012 in the Owner table. What is the result? (Use only the data in the tables below. Do not assume other data exists if it is not present in the tables below.) The primary keys are underlined. These are the OwnerNum column in the Owner table and the PetNumber in the Pet table. The foreign key is italicized. This is the OwnerNum column in the Pet table. Owner Table OwnerNum LastName FirstName Address City State Zip 005 Smith Jim 100 Main Dune FL 37465 009 Jones Jane 3245 West Sanford FL 32773 012 Johnson Frank 2 Century Easton FL 37256 020 Doe Sally 101 Basel Orange FL 30998 Pet Table PetNumber PetName DOB Species OwnerNum 100 Fido 1/1/2005 Canine 009 200 Ajax 12/3/2003 Canine 020 300 Sunshine 6./12/2004 Feline 009 400 King…Create a view named ITEM_INVOICE. It consists of the item ID, description, price, invoice number, invoice date, number ordered, and quoted price for all invoice lines currently on file.I need the output of the queries create table Accounts (account_no number primary key, client_name varchar2(200),Gender varchar2(20),address Varchar2(200)); create table loans (branch_id number, bank_name varchar2(200),Loan number, loan_Status varchar2(200),account_no number references Accounts(account_no) ON DELETE CASCADE); 1. delete from accounts where account_no= 101; 2. select * from accounts a where exists (select 1 from loans l where l.account_no= a.account_no) 3. select * from accounts a where exists (select 1 from loans l where l.account_no= a.account_no and status = 'accepted') 4. create or replace view view1 as select client_name , address,l.bank_name,l.loan_Status from accounts a, loans l where a.account_no = l.account_no Step 2 5.create or replace view view2 as select client_name , address,l.bank_name,l.loan_Status from accounts a, loans l where a.account_no = l.account_no and address = 'Karachi' 6. create or replace view view3 as select client_name ,…
- Task 6: The Car Maintenance team considered that the available maintenance tasks should also have the price information in the database. Alter the MAINTENANCE_TYPES table to include a new column named MAINTENANCE_PRICE of type FLOAT. ANSWER IN MYSQL PLEASEIf including downvote so far as well incorrectly. Create two different forms of the INSERT command to add a student with a student ID of 65798 and last name Lopez to the STUDENT table. Now write a command that will remove this student from the STUDENT table. How would your command look like if your task was to remove any student with the last name Lopez from the STUDENT table? Create an SQL command that will modify the name of course ISM 4212 from Database to Introduction to Relational Databases..The BLOOD_ADMIN_INFO are ORDER ID and LINE. The MAR_ADMIN_INFO MAR_BLOOD_INFO_LN table has one row per blood unit associated with an order. Its primary key columns table has one row per medication administration. The columns ORDER_MED_ID and form the foreign key to the BLOOD_ADMIN_INFO table. Use the followin*query to answer the question below it- SELECT mar.ORDER_MED_ID, mar.SCHEDULED_TIME, mar.TAKEN TIME, bld.BLOOD_ADMIN_TYPE FROM MAR_ADMIN_INFO as mar INNER JOIN BLOOD_ADMIN_INFO as bld What join condition is appropriate in ? AS [Blood Type] Select on of the following: A. mar.ORDER_MED_ID = bld.ORDER_ID B. mar.MAR_BLOOD_INFO_LN = bld.LINE C. mar.ORDER_MED_ID = bld.ORDER_ID AND mar.MAR_BLOOD_INFO_LN = bld.LINE D. It is not possible to join these tables
- Task 2: StayWell is an active business and already has some data collected over e-mails and phone conversations. You need to insert the following data to the OWNER and PROPERTY tables: Add the provided information to the OWNER table. Add the provided information to the PROPERTY table.For this problem create a (temporary) table called instructor_course_nums. Write a procedure that accepts an instructor ID as input. The procedure calculates the total number of course sections taught by that instructor, and adds a tuple to the temporary table consisting of the instructors ID number, name, and total courses taught - call these attributes: ID, name, and tot_courses. If the instructor already has an entry in the table,then the procedure makes sure the total number of courses taught in the temporary table is up-to-date. You must name your procedure: Written in PostgreSQLDatabase course: a. Add attribute deptId to the table course. b. Update deptId in table course of course NW3101 to “NW”. c. Create a view named batch1 that contains student id, student name and the department name of all students.
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