Use the following query to answer the question below it: SELECT PAT_NAME"Patient" ,PAT_ID "Patient ID" ,PROV NAME "Discharge Provider" ,PROV_NAME "Admitting Provider" ,DEPARTMENT_NAME "Discharge Department" FROM PAT_ENC_HSP INNER JOIN PATIENT ON PAT_ENC_HSP.PAT_ID = PATIENT.PAT_ID INNER JOIN CLARITY DEP ON PAT_ENC_HSP.DEPARTMENT_ID = CLARITY DEP. DEPARTMENT_ID INNER JOIN CLARITY_SER ON PAT_ENC_HSP.ADMISSION_PROV_ID = CLARITY_SER.PROV_ID INNER JOIN CLARITY_SER ON PAT_ENC_HSP.DISCHARGE_PROV_ID = CLARITY_SER.PROV_ID WHERE HOSP_DISCH_TIME IS NOT NULL Which table from this query must be aliased? Select one of the following: A. Patient B. PAT_ENC_HSP C. CLARITY_SER D. CLARITY_DEP

Use the following query to answer the question below it: SELECT PAT_NAME"Patient" ,PAT_ID "Patient ID" ,PROV NAME "Discharge Provider" ,PROV_NAME "Admitting Provider" ,DEPARTMENT_NAME "Discharge Department" FROM PAT_ENC_HSP INNER JOIN PATIENT ON PAT_ENC_HSP.PAT_ID = PATIENT.PAT_ID INNER JOIN CLARITY DEP ON PAT_ENC_HSP.DEPARTMENT_ID = CLARITY DEP. DEPARTMENT_ID INNER JOIN CLARITY_SER ON PAT_ENC_HSP.ADMISSION_PROV_ID = CLARITY_SER.PROV_ID INNER JOIN CLARITY_SER ON PAT_ENC_HSP.DISCHARGE_PROV_ID = CLARITY_SER.PROV_ID WHERE HOSP_DISCH_TIME IS NOT NULL Which table from this query must be aliased? Select one of the following: A. Patient B. PAT_ENC_HSP C. CLARITY_SER D. CLARITY_DEP

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Q: EmployeelD Last Name First Name Address City Province PostalCode Phone BirthDate 507 - 20th Ave.…

A: 1- A trigger is created for AFTER insert situation. 2- When a row is inserted, a copy of the row is…

Q: SELECT name FROM instructor WHERE name LIKE % dar_ Which of the instructor names will NOT be…

A: The names “Alimdarr” and “Alimdar” will NOT be included in the result of given query. Hence the…

Q: Write a Query First to Alter Table to add a new Column managername to the employee table…

A: Q: Write a Query First to Alter Table to add a new Column managername to the employee table…

Q: Write a SQL statement to create a foreign key in table Invoice_Detail that refers to the…

A: Write a SQL statement to create a foreign key in table Invoice_Detail that refers to the…

Q: what is wrong with this query: Select Title,count(Rental_ID) as…

A: The query seems to be missing a join condition to link the Rental table with the Film and Inventory…

Q: this is the code i run in sql developer CREATE TABLE MARKETING_CAMPAIGN( MACampID int,

A: CREATE TABLE MARKETING_CAMPAIGN(MACampID int,MACampName varchar(30) not null,MACampDescr…

Q: a. Find all movies with a cost less than or equal to the average moVies cost b. Write a query to…

A: Select Query: It will retrieve data from the table. select * from table name;…

Q: What values are returned while the given query is executed? SELECT 2* (Balance - Payment) FROM…

A: The query selects the result of the expression 2*(Balance - Payment) for each row in the "Customer"…

Q: please assist with the following questions. need to write a syntax in SQL server. Create an UPDATE…

A: It is defined as SQL (pronounced "ess-que-el") stands for Structured Query Language. SQL is used to…

Q: Question 6 List classroom ID, building name, class ID and class description. Use a LEFT JOIN to…

A: Here , i create one database and then In table i inserted some value by own.. then writing…

Q: The Driver Relationship team wants to ensure that the all driving license IDs in the active drivers…

A: This is a alter command in mysql to add check in already created table.

Q: Write a query that uses INNER JOIN TO connect the EMPLOYEE, EMPPROJACT, PROJACT and PROJECT tables.…

A: The INNER JOIN is also referred as EQUIJOIN.The EQUIJOIN creates a new result table by combining…

Q: Which clause can be used to restrict or filter the groups returned by a group function- based query?

A: The HAVING Clause is used to filter data from groups depending on a condition that is specified in…

Q: 1) Rewrite the query below to use GROUP BY CUS_CODE : SELECT CUSTOMER.CUS_CODE,…

A: In step 2, you will get the answer for 1. In step 3, you will get the answer for 2. In step 4, you…

Q: Create a new table, EMP_PROMOTION to store the employees information. You must use a subquery to…

A: Objective: A table "EMP_PROMOTION" would be created using sub-query from an existing relation…

Concept explainers

SQL Query

Structured Query Language is the full form of SQL. It is one of the standard languages to deal with the relational database. It is used to insert, update, delete, and search the records stored in a RDBMS. The relational databases are created and managed by using SQL.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Introduction Defining aliasing

VIEW

Step 2: Solution of Qusetion based on Query

VIEW

Step 3: Why Other options are incorrect

VIEW

Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions

Write an SQL query that will select OrderID and OrderDate from theOrders table and OrderDetailID from the OrderDetails table. The queryshould join on the Orders table using the OrderID attribute.
Which type of join is demonasted by the folloing query? Select from make. model where make modelID to mode ID a) Non-Equlion b) Self Join c) Cross Join d) Equijoin
Create a table in SQL developer and name it as ‘MyCrush’. The table should consists of only three attributes as follows: Crush_ID which will be the primary key with the number length of .Crush_Name with the maximum character length of 30.Crush_Description with the maximum character length of 10.Insert exactly three records with the above given attributes. Crush_ID values should be 1, 2 and 3 for the three records. Crush_Description should be ‘Present’ for record 1, ‘Past’ for record 2 and ‘Childhood’ for record 3. If you don’t have any crush from your childhood to present, you can insert some random names. Hmm.. Seems Interesting!! It’s time to implement your programming skills using PL/SQL stored procedures and functions. Create another table called ‘MyDetails’ and should contain exactly four attributes as below: Student_ID,Student_Name ,Student_Term ,Student_GPA If you are not a Master’s student, let’s assume you are a student pursuing masters and taking four semesters or terms.…
Create a View to show the city name of any location that has a department. Only show the city name once in the results. You must use a non-correlated subquery.Call this view: Department_LocationsInclude a second query to display from the View after it is created. Refer to the attached for the table.
The BLOOD_ADMIN_INFO are ORDER ID and LINE. The MAR_ADMIN_INFO MAR_BLOOD_INFO_LN table has one row per blood unit associated with an order. Its primary key columns table has one row per medication administration. The columns ORDER_MED_ID and form the foreign key to the BLOOD_ADMIN_INFO table. Use the followin*query to answer the question below it- SELECT mar.ORDER_MED_ID, mar.SCHEDULED_TIME, mar.TAKEN TIME, bld.BLOOD_ADMIN_TYPE FROM MAR_ADMIN_INFO as mar INNER JOIN BLOOD_ADMIN_INFO as bld What join condition is appropriate in ? AS [Blood Type] Select on of the following: A. mar.ORDER_MED_ID = bld.ORDER_ID B. mar.MAR_BLOOD_INFO_LN = bld.LINE C. mar.ORDER_MED_ID = bld.ORDER_ID AND mar.MAR_BLOOD_INFO_LN = bld.LINE D. It is not possible to join these tables
JOIN TABLES One row in the PAT_ENC table represents one patient encounter. One row in the ORDER MED table represents one medication order. One patient encounter can have many medication orders but one medication order can only have one patient encounter. In other words, the cardinality of this PAT_ENC to ORDER_MED relationship is one-to- many. You start a query with PAT_ENC. You then add ORDER_MED using an inner join. What is true about the granularity of the result set before and after adding the ORDER_MED table? SELECT ONE OF THE FOLLOWING A. The granularity stays at one row per patient encounter. B. The granularity stays at one row per medication order. C. The granularity changes from one row per patient encounter to one row per medication order on an encounter. D. The granularity changes from one row per medication order to one row per patient encounter.
Write a SQL query to find the customer# of those customers that purchased at least once in July 2020 but NOT in August 2020. In addition to the customer#, show the ISBN and title of the book(s) they purchased in July 2020. You may use only one query. No creating any temporary tables or subqueries. You may use only joins. SUBMIT a second solution in addition to your Level 1.
Hi triggers Update and using Xampp and this table: CREATE TABLE MEMBER(STUDENT_ID CHAR(6) NOT NULL,CLUB_CODE VARCHAR(4) NOT NULL,MEMBER_DATE DATE NOT NULL,MEMBER_POSITION VARCHAR(15) NOT NULL,MEMBER_ATTENDANCE CHAR(2) NOT NULL,PRIMARY KEY (STUDENT_ID,CLUB_CODE),FOREIGN KEY (STUDENT_ID) REFERENCES STUDENT (STUDENT_ID) ON DELETE RESTRICT ON UPDATE CASCADE,FOREIGN KEY (CLUB_CODE) REFERENCES CLUB (CLUB_CODE) ON DELETE RESTRICT ON UPDATE CASCADE); INSERT INTO MEMBER VALUES('100027','C201','2020-03-25','Secretary','12'),('100027','C202','2020-04-11','Member','11'),('100032','C201','2020-02-23','President','12'),('100050','C201','2020-03-25','Member','10'),('100132','C202','2020-04-11','Treasurer','10'),('100074','C203','2020-04-09','President','12'),('100074','C204','2020-04-25','Treasurer','12'),('100051','C204','2020-04-25','Member','9'),('100064','C207','2020-04-25','Vice…