1. Write the reverse string() function for the given code below.(Hint: use strlen() function which gives the length of a string.)#include #include 1.23void reverse_string (char str []);4int main (){7char str_arr[100];8.printf ("Enter a string :");scanf ("%s", str_arr);reverse string (str_arr);printf ("Reversed string is: %s \n", str_arr);1011121314return 0;15}16

Algorithm for string reverse function,reverse_string : 1. Get the length of the cstring using…

Write the reverse string() function for the given code below. (Hint: use strlen() function which gives the length of a string.) #include #include void reverse_string(char str[]); int main () { char str_arr[100]; printf("Enter a string :"); scanf("%s", str_arr); reverse string(str_arr); printf("Reversed string is: %s \n", str_arr); return 0; }

Write the reverse string() function for the given code below. (Hint: use strlen() function which gives the length of a string.) #include #include void reverse_string(char str[]); int main () { char str_arr[100]; printf("Enter a string :"); scanf("%s", str_arr); reverse string(str_arr); printf("Reversed string is: %s \n", str_arr); return 0; }

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include <bits/stdc++.h>using namespace std; int main() { string str; cout << "Enter a string: "; getline (cin, str); for(int i=0; i<str.length(); i++){ if(str[i]=='a' || str[i]=='e' || str[i]=='i' || str[i]=='o' || str[i]=='u' || str[i]=='A' || str[i]=='E' || str[i]=='I' || str[i]=='O' || str[i]=='U'){ str[i] = '*'; } } cout<<"Resulting string: "<<str; return 0; WHAT DOES THE FOR LOOP MEAN HERE? PLEASE EXPLAIN for(int i=0; i<str.length(); i++){
Algorithm for the below program #include<stdio.h>#include<stdlib.h>#include<string.h> //structuretypedef struct{char Username [20];int cents;} value; int *coin Change (int change); //main functionint main () { FILE *f; //open the filef = f open ("coins.txt", "r"); //check if file not openedif(f==NULL){printf ("File not opened!");return 1;} value arr [10];int i, j, n, option, totalCoins;char name [20];int *coins; // = //read the filefor (i=0;!feof(f) ; i++){fscanf(f, "%s", arr[i].Username);fscanf(f, "%d", &arr[i].cents);} n = i; //close the filefclose(f); //loopwhile (1){//display menuprintf ("1. Enter name\n");printf ("2. Exit\n\n"); //prompt and read optionprintf ("Enter option (1 or 2): ");scanf ("%d", &option); //switch statementswitch(option){case 1://read the namescanf ("%s", name);totalCoins = 0;//search in the listfor(i=0; i<n; i++){if(!strcmp(name, arr[i].Username)){totalCoins = totalCoins + arr[i].cents;}}//check if not…
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#include<stdio.h>#include<string.h>struct info{char names[100];int age;float wage;};int main(int argc, char* argv[]) {int line_count = 0;int index, i;struct info hr[10];if (argc != 2)printf("Invalid user_input!\n");else {FILE* contents = fopen (argv[1], "r");struct info in;if (contents != NULL) {printf("File has been opened successfully.\n\n");while (fscanf(contents, "%s %d %f\n",hr[line_count].names, &hr[line_count].age, &hr[line_count].wage) != EOF) {printf("%s %d %f\n", hr[line_count].names, hr[line_count].age, hr[line_count].wage);line_count++;}printf("\nTotal number of lines in document are: %d\n\n", line_count);fclose(contents);printf("Please enter a name: ");char user_input[100];fgets(user_input, 30, stdin);user_input[strlen(user_input)-1] = '\0';index = -1;for(i = 0; i < line_count; i++){if(strcmp(hr[i].names, user_input) == 0){index = i;break;}}if(index == -1)printf("Name %s not found\n", user_input);else{while(fread(&in, sizeof(struct info), 1,…
C++language
Scala Programming: Given string str, write a Scala program to create a new string where "Scala " is added to the front of a given string. If the string already begins with "Scala", return the string unchanged. Otherwise, return the string after adding "Scala ". Test the function for two strings "Scala Programming" and "Programming" inside the main method.
#include using namespace std; void scanPrice (string [], double []); // Do not modify the code double printReceipt(string [], double[]); // Do not modify the code int main () { double sum; string item [3] = {"Vegetable","Egg", "Meat"}; double price [3];| %3D scanPrice (item,price); sum = RrintReceipt (item,price); cout Price: 10 The price of Vegetable is RM 2 The price of Egg is RM 3 The price of Meat is RM 10 Your total expenses is RM 15
please use DEQUE #include <iostream>#include <string>#include <deque> using namespace std; const int AIRPORT_COUNT = 12;string airports[AIRPORT_COUNT] = {"DAL","ABQ","DEN","MSY","HOU","SAT","CRP","MID","OKC","OMA","MDW","TUL"}; int main(){// define stack (or queue ) herestring origin;string dest;string citypair;cout << "Loading the CONTAINER ..." << endl;// LOAD THE STACK ( or queue) HERE// Create all the possible Airport combinations that could exist from the list provided.// i.e DALABQ, DALDEN, ...., ABQDAL, ABQDEN ...// DO NOT Load SameSame - DALDAL, ABQABQ, etc .. cout << "Getting data from the CONTAINER ..." << endl;// Retrieve data from the STACK/QUEUE here } Using the attached shell program (AirportCombos.cpp), create a list of strings to process and place on a STL DEQUE container. Using the provided 3 char airport codes, create a 6 character string that is the origin & destination city pair. Create all the possible…
WAP c# program creates a string, s1, which deliberately leaves space for a name, much like you’d do with a letter you plan to run through a mail merge. We add two to the position where we find the comma to make sure there is a space between the comma and the name.
#include<iostream>#include<string>#include <cstdlib>#include <ctime>#include<time.h>#include <iomanip>using namespace std; void merge(string a[], string b[], int left, int mid, int right) {int nL = mid - left + 1;int nR = right - mid;string leftA[nL], rightA[nR], leftB[nL], rightB[nR];for(int i = 0; i < nL; i++) {leftA[i] = a[nL+i];leftB[i] = b[nL+i];}for(int i = 0; i < nR; i++) {rightA[i] = a[mid+i+1];rightB[i] = b[mid+i+1];}int i = 0, j = 0, k = left;while(i < nL && j < nR) {if(leftA[i] <= rightA[j]) {a[k] = leftA[i];b[k] = leftB[i];i++;}else {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}}while(i < nL) {a[k] = leftA[i];b[k] = leftB[i];i++;k++;}while(j < nR) {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}} void mergeSort(string a[], string b[], int left, int right) {int mid;if(left < right) {mid = left + (right-1)/2;mergeSort(a,b,left,mid);mergeSort(a,b,mid+1,right);merge(a,b,left,mid,right);}} int menu() {int…
#include<bits/stdc++.h>using namespace std;bool isPalindrome(string &s){ int start=0; int end=s.length()-1; while(start<=end) { if(s[start]!=s[end]) { return false; } start++; end--; } return true;}int main(){ string s; cout<<"ENTER STRING:"; getline(cin,s); int n=s.length(); bool flag=true; for(int i=1;i<n;i++) { string lowerHalf=s.substr(0,i); string upperHalf=s.substr(i,n-i); if(isPalindrome(lowerHalf) && isPalindrome(upperHalf)) { flag=false; cout<<"String A is:"<<lowerHalf<<"\n"; cout<<"String B is:"<<upperHalf<<"\n"; break; } } if(flag) { cout<<"NO\n"; } return 0;} change to stdio.h string.h
#include <iostream> using namespace std; int main(){ int a[100],n,i,item,loc=0; cout<<"Enter number of elements: "; cin>>n; cout<<"\nEnter numbers:\n"; for(i=1;i<=n;i++) { cin>>a[i]; } cout<<"\nEnter number to search:"; cin>>item; for(i=1;i<=n;i++) { if(item==a[i]) { loc=i; break; } } if(loc>0) { cout<<loc<<" is the location of item"; } else cout<<"\nno. not found";} Q: edit the code that shows after how many number of iteration searched value is found