Write the equilibrium constant expression, K, for the following reaction. Please enter the compounds in the order given in the reaction. If either the numerator or denominator is blank, please enter 1 HCN (aq) + H₂O(1) H3O+ (aq) + CN- (aq) K=

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Chapter1: Chemical Foundations
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**Equilibrium Constant Expression for a Chemical Reaction**

To determine the equilibrium constant expression, K, for the given reaction:

\[ \text{HCN (aq)} + \text{H}_2\text{O (l)} \rightleftharpoons \text{H}_3\text{O}^+ \text{(aq)} + \text{CN}^- \text{(aq)} \]

**Instructions:**
- Enter the compounds in the order they appear in the reaction.
- If either the numerator or denominator is blank, enter the value 1.

**Reaction Expression:**

For this reaction, the equilibrium constant expression, K, is written as:

\[ K = \frac{[\text{H}_3\text{O}^+][\text{CN}^-]}{[\text{HCN}]} \]

Since \(\text{H}_2\text{O}\) is a liquid, its concentration is not included in the equilibrium expression.
Transcribed Image Text:**Equilibrium Constant Expression for a Chemical Reaction** To determine the equilibrium constant expression, K, for the given reaction: \[ \text{HCN (aq)} + \text{H}_2\text{O (l)} \rightleftharpoons \text{H}_3\text{O}^+ \text{(aq)} + \text{CN}^- \text{(aq)} \] **Instructions:** - Enter the compounds in the order they appear in the reaction. - If either the numerator or denominator is blank, enter the value 1. **Reaction Expression:** For this reaction, the equilibrium constant expression, K, is written as: \[ K = \frac{[\text{H}_3\text{O}^+][\text{CN}^-]}{[\text{HCN}]} \] Since \(\text{H}_2\text{O}\) is a liquid, its concentration is not included in the equilibrium expression.
Expert Solution
Step 1

Given reaction: HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN-(aq)

We have to write the expression of the equilibrium constant for this reaction.

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