Write a skeleton equation for each chemical reaction. Indicate the state of each reactant and product in the skeleton equation. Remember that the following seven elements are diatomic: hydrogen, H2(g); nitrogen, N2(g); oxygen, O2(g); fluorine, F2(g); chlorine, Cl2(g); bromine, Br2(l); and iodine, I,(s). 5. When aqueous solutions of silver nitrate and sodium chloride are combined, the reaction produces an aqueous solution of sodium nitrate and a precipitate of silver chloride. 9. Solid aluminum and gaseous fluorine form when solid aluminum fluoride breaks down.
Write a skeleton equation for each chemical reaction. Indicate the state of each reactant and product in the skeleton equation. Remember that the following seven elements are diatomic: hydrogen, H2(g); nitrogen, N2(g); oxygen, O2(g); fluorine, F2(g); chlorine, Cl2(g); bromine, Br2(l); and iodine, I,(s). 5. When aqueous solutions of silver nitrate and sodium chloride are combined, the reaction produces an aqueous solution of sodium nitrate and a precipitate of silver chloride. 9. Solid aluminum and gaseous fluorine form when solid aluminum fluoride breaks down.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Write a skeleton equation for each chemical reaction.
Indicate the state of each reactant and product in the
skeleton equation. Remember that the following seven
elements are diatomic: hydrogen, H2(g); nitrogen, N2(g);
oxygen, O2(g); fluorine, F2(g); chlorine, Cl½(g); bromine,
Br2(l); and iodine, I½(s).
5. When aqueous solutions of silver nitrate and sodium
chloride are combined, the reaction produces an
aqueous solution of sodium nitrate and a precipitate
of silver chloride.
9. Solid aluminum and gaseous fluorine form when
solid aluminum fluoride breaks down.
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