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Write a mechanism that accounts for the formation of ethyl isopropyl ether as one of the products in the following reaction. CI OEt Write the mechanism for step two of this reaction (where the product of step one reacts with the solvent, ethanol). Show lone pairs and formal charges. Only the acidic hydrogen should be drawn out with a covalent bond. H₂C H₂C Edit Drawing CH₂ H₂C Write the mechanism for the last step of this reaction (formation of ethyl isopropyl ether). Show lone pairs and formal charges. Only the acidic hydrogen should be drawn out with a covalent bond. CI will act as the base in this reaction. CH₂ Edit Drawing HCI EtOH QEt +HCI CH₂₁

Write a mechanism that accounts for the formation of ethyl isopropyl ether as one of the products in the following reaction. CI OEt Write the mechanism for step two of this reaction (where the product of step one reacts with the solvent, ethanol). Show lone pairs and formal charges. Only the acidic hydrogen should be drawn out with a covalent bond. H₂C H₂C Edit Drawing CH₂ H₂C Write the mechanism for the last step of this reaction (formation of ethyl isopropyl ether). Show lone pairs and formal charges. Only the acidic hydrogen should be drawn out with a covalent bond. CI will act as the base in this reaction. CH₂ Edit Drawing HCI EtOH QEt +HCI CH₂₁

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please help me with the last two steps. I keep getting them marked wrong. Please and thank you!

**Formation of Ethyl Isopropyl Ether Mechanism** **Overview:** This section outlines the mechanism by which ethyl isopropyl ether is formed as one of the products in the given reaction involving hydrochloric acid (HCl) and ethanol (EtOH). **Reaction Description:** The starting materials react to form two products: isopropyl chloride (Cl) and ethyl isopropyl ether (OEt). **Step 2 Mechanism:** - This step involves the reaction of the intermediate product with ethanol. - The diagram shows: - A curved arrow indicating the movement of electron pairs. - Lone pairs and formal charges on atoms. - The acidic hydrogen is shown with a covalent bond. **Final Step Mechanism:** - This step illustrates the formation of ethyl isopropyl ether. - The diagram includes: - The departure of chloride ion (Cl⁻) acting as the base. - Movement of electron pairs using curved arrows. - Emphasis on lone pairs and formal charges. - The covalent bond to the acidic hydrogen is highlighted. These diagrams guide learners in understanding the electron flow and structural changes within the reaction, crucial for mastering organic reaction mechanisms.
Transcribed Image Text:**Formation of Ethyl Isopropyl Ether Mechanism** **Overview:** This section outlines the mechanism by which ethyl isopropyl ether is formed as one of the products in the given reaction involving hydrochloric acid (HCl) and ethanol (EtOH). **Reaction Description:** The starting materials react to form two products: isopropyl chloride (Cl) and ethyl isopropyl ether (OEt). **Step 2 Mechanism:** - This step involves the reaction of the intermediate product with ethanol. - The diagram shows: - A curved arrow indicating the movement of electron pairs. - Lone pairs and formal charges on atoms. - The acidic hydrogen is shown with a covalent bond. **Final Step Mechanism:** - This step illustrates the formation of ethyl isopropyl ether. - The diagram includes: - The departure of chloride ion (Cl⁻) acting as the base. - Movement of electron pairs using curved arrows. - Emphasis on lone pairs and formal charges. - The covalent bond to the acidic hydrogen is highlighted. These diagrams guide learners in understanding the electron flow and structural changes within the reaction, crucial for mastering organic reaction mechanisms.
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