Attached is a question about a loop in my lab. We are using java and I am lost. ### Loop to Count Specific Characters in a String**Problem Statement:**Write a loop that iterates over a `String` `s` and counts, then prints the total number of x’s plus y’s, plus z’s combined. *(i.e. if `s` = `"xyzdddfgx"` your code should print 4)***Detailed Explanation:**1. **Objective:** The task is to write a loop in a programming language (such as Python, Java, etc.) that will go through each character in a string and keep a count of how many times the characters 'x', 'y', and 'z' appear.2. **Example:** - If the input string is `"xyzdddfgx"`, the output should be `4`, because the characters 'x', 'y', and 'z' appear a total of 4 times in the string.#### Steps to Solve the Problem:1. **Initialize a Counter:** - Start by initializing a counter to zero. This counter will keep track of the total number of specific characters ('x', 'y', 'z') encountered in the string.2. **Iterate Over the String:** - Use a loop to go through each character in the string `s`.3. **Check for Specific Characters:** - During each iteration, check if the current character is either 'x', 'y', or 'z'. - If it is, increment the counter by one.4. **Print the Result:** - After the loop has finished, print the value of the counter, which is the total number of 'x's, 'y's, and 'z's in the string.#### Example Code in Python:```python# Example Strings = "xyzdddfgx"# Initialize the countercount = 0# Loop through each character in the stringfor char in s: # Check if the character is 'x', 'y', or 'z' if char in ['x', 'y', 'z']: # Increment the counter count += 1# Print the resultprint(count)```### Visual AidThere are no graphs or diagrams associated with this problem. The explanation mainly involves understanding the logic of iteration and conditional counting within a string.

import java.util.*;public class Main{ public static void main(String[] args) { int countx=0;…

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Write a loop that iterates over a String s and counts, then prints the total number of x's plus y's, plus z's combined. (i.e. if s = "xyzdddfgx" your code should print 4)

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Attached is a question about a loop in my lab. We are using java and I am lost.

### Loop to Count Specific Characters in a String

**Problem Statement:**

Write a loop that iterates over a `String` `s` and counts, then prints the total number of x’s plus y’s, plus z’s combined. *(i.e. if `s` = `"xyzdddfgx"` your code should print 4)*

**Detailed Explanation:**
1. **Objective:** The task is to write a loop in a programming language (such as Python, Java, etc.) that will go through each character in a string and keep a count of how many times the characters 'x', 'y', and 'z' appear.
2. **Example:**
- If the input string is `"xyzdddfgx"`, the output should be `4`, because the characters 'x', 'y', and 'z' appear a total of 4 times in the string.

#### Steps to Solve the Problem:
1. **Initialize a Counter:**
- Start by initializing a counter to zero. This counter will keep track of the total number of specific characters ('x', 'y', 'z') encountered in the string.
2. **Iterate Over the String:**
- Use a loop to go through each character in the string `s`.
3. **Check for Specific Characters:**
- During each iteration, check if the current character is either 'x', 'y', or 'z'.
- If it is, increment the counter by one.
4. **Print the Result:**
- After the loop has finished, print the value of the counter, which is the total number of 'x's, 'y's, and 'z's in the string.

#### Example Code in Python:
```python
# Example String
s = "xyzdddfgx"

# Initialize the counter
count = 0

# Loop through each character in the string
for char in s:
# Check if the character is 'x', 'y', or 'z'
if char in ['x', 'y', 'z']:
# Increment the counter
count += 1

# Print the result
print(count)
```

### Visual Aid

There are no graphs or diagrams associated with this problem. The explanation mainly involves understanding the logic of iteration and conditional counting within a string.

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