Write a C program to sort a list of elementsusing the insertion sort algorithm.Note:Insertion sort is a simple sorting algorithm thatbuilds the final sorted array (or list) one item at atime. It is much less efficient on large lists thanother algorithms such as quicksort, heapsort, ormerge sort.

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Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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**Cenaage Python** Question: A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary. CODE: def sequentialSearch(target, lyst): """Returns the position of the target item if found, or -1 otherwise. The lyst is assumed to be sorted in ascending order.""" position = 0 while position < len(lyst): if target == lyst[position]: return position position += 1 return -1 def main(): """Tests with three lists.""" print(sequentialSearch(3, [0, 1, 2, 3, 4])) print(sequentialSearch(3, [0, 1, 2])) # Should stop at second position. print(sequentialSearch(3, [0, 4, 5, 6])) if __name__ == "__main__": main()
python LAB: Subtracting list elements from max When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This can be done by normalizing to values between 0 and 1, or throwing away outliers. Write a program that adjusts a list of values by subtracting each value from the maximum value in the list. The input begins with an integer indicating the number of integers that follow.
Write a program to sort an array of random elements using quicksort as follows: Sort the arrays using pivot as the first element of the array Sort the arrays using pivot as the median of the first, last, and middle elements of the array Sort the arrays using pivot as the first element of the array. However,, when the size of any sub-list reduces to less than 20, sort the sub-list using insertion sort. Sort the array using pivot as the median of the first, last and middle elements of the array. When the size of any sub-list reduces to less than 20, sort the sub-list using insertion sort. Calculate and display the CPU time for each of the preceding four steps. Example of the median of the first, last and middle elements: 1 2 3 4 5 6 7 8 0 (median of 1, 5, 0 is 1) 8 0 1 2 3 4 5 6 7 (median of 8, 3, 7 is 7) To calculate the CPU time, use the header , and clock_t type. You need to cast the duration to float and divide it by CLOCKS_PER_SEC. Depends on the CPU of your computer, your…
Write code in assembly language Question 1: Construct a program using 2D array. Define a list of strings in the 2D arrays, the list should be only a string. Get a string from a user as input Search the user's string in the list of strings. If string is found print the string, and a message "String is Found". If string is not found print only a message "String is Not Found".
Quick Sort We choose an element from the list, called the pivot. We'll use it to divide the list into two sub-lists. We reorder all the elements around the pivot The ones with smaller value are placed before it All the elements greater than the pivot after it. After this step, the pivot is in its final position. This is the important partition step. We apply the above steps recursively to both sub-lists on the left and right of the pivot. Quick Sort (Example) Consider the following array Arr[] = {5, 9, 4, 6, 5, 3} Let's suppose we pick 5 as the pivot for simplicity We'll first put all elements less than 5 in the first position of the array: {3, 4, 5, 6, 5, 9} We'll then repeat it for the left sub-array {3,4}, taking 3 as the pivot There are no elements less than 3 We apply quicksort on the sub-array in the right of the pivot, i.e. {4} This sub-array consists of only one sorted element We continue with the right part of the original array, {6, 5, 9} until we get the final ordered…
Python data structures: write a function that takes in a list (L) as input, and returns the number of inversions. An inversion in L is a pair of elements x and y such that x appears before y in L, but x > y. Your function must run in -place and implement the best possible algoritm of time complexity. def inversions(L: List) -> int:'''finds and returns number of inversions'''
Complete the recursive function remove_last which creates a new list identical to the input list s but with the last element in the sequence that is equal to x removed. Hint: Remember that you can use negative indexing on lists! For example 1st [-1] refers to the last element in a list 1st, lst [-2] refers to the second to last element... def remove_last(x, s): """Create a new list that is identical to s but with the last element from the list that is equal to x removed. >>> remove_last(1, []) [] >>> remove_last(1, [1]) [] >>> [1] >>> [2] remove_last(1, [1,1]) remove_last(1, [2,1]) >>> remove_last(1, [3,1,2]) [3, 2] >>> remove_last(1, [3,1,2,1]) [3, 1, 2] >>> remove_last (5, [3, 5, 2, 5, 11]) [3, 5, 2, 11] IIIII "*** YOUR CODE HERE ***" Illustrated here is a more complete doctest that shows good testing methodology. It is a little cumbersome as documentation, but you'll want to think about it for your projects. Test every condition that might come up. Then you won't be surprised when…
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A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary. ----------------------------------------------------------------------------------- """ File: search.py Project 11.1 """ def sequentialSearch(target, lyst): """Returns the position of the target item if found, or -1 otherwise. The lyst is assumed to be sorted in ascending order.""" position = 0 while position < len(lyst): if target == lyst[position]: return position position += 1 return -1 def main(): """Tests with three lists.""" print(sequentialSearch(3, [0, 1, 2, 3, 4])) print(sequentialSearch(3, [0, 1, 2])) # Should stop at second position. print(sequentialSearch(3, [0, 4, 5, 6])) if…

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