**Cenaage Python** Question: A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary. CODE: def sequentialSearch(target, lyst): """Returns the position of the target item if found, or -1 otherwise. The lyst is assumed to be sorted in ascending order.""" position = 0 while position < len(lyst): if target == lyst[position]: return position position += 1 return -1 def main(): """Tests with three lists.""" print(sequentialSearch(3, [0, 1, 2, 3, 4])) print(sequentialSearch(3, [0, 1, 2])) # Should stop at second position. print(sequentialSearch(3, [0, 4, 5, 6])) if __name__ == "__main__": main()

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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**Cenaage Python** Question: A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary.

CODE:

def sequentialSearch(target, lyst):
    """Returns the position of the target item if found,
    or -1 otherwise.
    The lyst is assumed to be sorted in ascending order."""
    position = 0
    while position < len(lyst):
        if target == lyst[position]:
            return position
        position += 1
    return -1

def main():
    """Tests with three lists."""
    print(sequentialSearch(3, [0, 1, 2, 3, 4]))
    print(sequentialSearch(3, [0, 1, 2]))
    # Should stop at second position.
    print(sequentialSearch(3, [0, 4, 5, 6]))

if __name__ == "__main__":
    main()
    
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