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- What are the components of a carbon-free broth or minimum medium for E.coli ? An example for broth without carbon to use for E.coli.use these OD numbers to plot growth curve for E. coli K12- and estimate generation time for this culture. Table 1. Absorbance (O.D.600) measured for growing culture of E. coli K12 (time course) Incubation time O.D.600 Incubation time O.D.600 O min 3 hrs 3 hrs 30 min 4 hrs 4 hrs 30 min 5 hrs 5 hrs 30 min 0.11 1.75 30 min 0.20 1.94 1 hr 1 hr 30 min 2 hrs 2 hrs 30 min 0.27 2.24 0.51 2.48 2.31 2.19 0.65 1.30You are cultivating Escherichia coli in a chemostat culture. The maximum specific growth rate (µmax) of E. coli that you can reach is known as 1.0 h-1 at your culture conditions. Describe what you would observe for each condition if you have the following settings: F (flow rate of the fresh medium into the bioreactor vessel) (L/h) V (Volume of the liquid culture in the bioreactor vessel) (L) a) 1 1 b) 5 4 c) 1 2
- N. benthamiana will be infiltrated with a solution containing OD600=0.3 of each experimental Agro containing construct and OD600=0.1 of p19. Calculate the volume of cultures (V construct; V p19) needed according to the formulas: V construct = V final × 0.3/OD600; V p19 = V final × 0.1/OD600. One mL of infiltrate is often enough to complete a small experiment. How to plan your final volume accordingly?A 3.0 L batch bioreactor is used to grow E. coli bacteria, which have an initial concentration of 12.5 g cells/L. The growth medium contains two carbon sources, which causes diauxic growth, with each carbon source limiting cell growth. Sufficient supplies of oxygen, ammonium nitrate (NH4NO3) as a nitrogen source and all other macro and micronutrients are available. The bacteria prefer to grow on glucose (C6H12O6, supplied at 80 g/L), so it is consumed first, followed by glycerol (C3H803, supplied at 68 g/L). Since the E. coli were already growing on glucose, the lag time associated with glucose consumption is only 10 minutes. The lag time associated with glycerol consumption is 35 minutes. Further information: The chemical formula for E. coli in this bioreactor is CH1.666N0.2000.57. The specific growth rate on glucose is 0.41 h-1, and on glycerol is 0.32 h-1?The yield of cells on glucose is 0.48 g cells/g glucose, and yield on glycerol is 0.39 g cells/g glycerol. You may assume that…A 3.0 L batch bioreactor is used to grow E. coli bacteria, which have an initial concentration of 12.5 g cells/L. The growth medium contains two carbon sources, which causes diauxic growth, with each carbon source limiting cell growth. Sufficient supplies of oxygen, ammonium nitrate (NH4NO3) as a nitrogen source and all other macro and micronutrients are available. The bacteria prefer to grow on glucose (C6H12O6, supplied at 80 g/L), so it is consumed first, followed by glycerol (C3H8O3, supplied at 68 g/L). Since the E. coli were already growing on glucose, the lag time associated with glucose consumption is only 10 minutes. The lag time associated with glycerol consumption is 35 minutes. Further information: The chemical formula for E. coli in this bioreactor is CH1.666N0.20O0.57. The specific growth rate on glucose is 0.41 h-1 , and on glycerol is 0.32 h-1 . The yield of cells on glucose is 0.48 g cells/g glucose, and yield on glycerol is 0.39 g cells/g glycerol. You may assume that…
- In growing E.coli, why is that (reasons) they do not grow after doubling time under 20 degrees celsius and under 37 degrees celsius, the number of colonies after doubling time has decreased? provide reliable sources (links).The data below were obtained for the growth of a pure culture of Escherichia coli in nutrient broth at a temperature of 37°C. Determine (1) the specific growth rate and (2) generation time of E. coli and the duration of the (3) lag and (4) log (or exponential) phases. (ln 2 = 0.693) Time (h) 0 1 2 3 4 8 16 32 Bacterial No./mL 104.1 103.9 104.4 105.5 106.5 107.7 108.0 107.6In a fed-batch culture operating with intermittent addition of lactose solution, values ofthe following parameters are given at time t = 2, when the system is at a quasi-steady state. 1.Determine the initial volume of the culture 2. Determine the concentration of growth-limiting substrate and the total amount ofbiomass in the vessel at a quasi-steady state. 3. At which scenario of bioprocessing, a fed-batch system is recommended to be applied?
- Two microorganisms that use naphthalene as a food source have the same Umax but different Ks values for naphthalene. If both types of microorganisms are inoculated at the same cell density into a liquid culture containing naphthalene as the sole carbon source (i.e. the only food source), which microorganism will outcompete the other: the one with the higher Ks or the one with the lower Ks. Why?.Consider the desired phenotype pattern of candidates that we wish to advance into experiments in Week 5 and beyond. If the growth patterns illustrated below are observed in your Week 4 results, which of the candidates would you select for further analysis? Select all that apply. Candidate A B A B C с = vigorous growth on this medium = impaired/slow growth on this medium = no growth on this medium SC-H B SC-K A B YP GalE. coli has a doubling time of 0.345 hours at 37 0C. Starting with 1 milligram of cells, assuming a lag phase of 30 minutes and a stationary phase of 30 minutes, what number of cells would you expect at the end of 13h, assuming that besides the lag and stationary phases the culture is continuously in exponential phase. Assume that ln (2) = 0.69 and that the mass of a single cell is 10^(-12) g.