Work Sheet Assignment 17 [Jacobian Elliptic Integral Length]: Find the arc-length function t > 0 → 1(t) (closed form mathematical expression, no series form, but depending on real parameters k > a > 0) of any positively oriented curve segment C of z values satisfying the equation (ellipse) |z – a| + |z + a| 2k by complex integration (For all constants k > a > 0), see CALEC18 – CALEC19, starting at x-axis point (k, 0). Note that the parameterization C : z(t) = (k-cos(t), Vk² – a²-sin(t)), t > 0 of the curve C starts at the intersection with x-axis, counterclockwise oriented. Provide all mathematical details step by step (not just final answers).

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Work Sheet Assignment 17 [Jacobian Elliptic Integral Length]: Find the arc-length function
t > 0 → 1(t) (closed form mathematical expression, no series form, but depending on real
parameters k > a > 0) of any positively oriented curve segment C of z values satisfying the
equation (ellipse)
|z – al + |z+ a|
2k
by complex integration (For all constants k > a > 0), see CALEC18
x-axis point (k, 0). Note that the parameterization C : z(t) = (k-cos(t), vk? – a²-sin(t)), t > 0
of the curve C starts at the intersection with x-axis, counterclockwise oriented.
Provide all mathematical details step by step (not just final answers).
CALEC19, starting at
Transcribed Image Text:Work Sheet Assignment 17 [Jacobian Elliptic Integral Length]: Find the arc-length function t > 0 → 1(t) (closed form mathematical expression, no series form, but depending on real parameters k > a > 0) of any positively oriented curve segment C of z values satisfying the equation (ellipse) |z – al + |z+ a| 2k by complex integration (For all constants k > a > 0), see CALEC18 x-axis point (k, 0). Note that the parameterization C : z(t) = (k-cos(t), vk? – a²-sin(t)), t > 0 of the curve C starts at the intersection with x-axis, counterclockwise oriented. Provide all mathematical details step by step (not just final answers). CALEC19, starting at
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