For x 2 0, prove the following identity: | = 2 arctan vx – arcsin + 1, 2 Hint: If f,g are differentiable for x > 0 and f'(x) = g'(x), then f(x) = g(x) + C, where C is a constant. In particular, f (0) = g(0) + C. %3D
For x 2 0, prove the following identity: | = 2 arctan vx – arcsin + 1, 2 Hint: If f,g are differentiable for x > 0 and f'(x) = g'(x), then f(x) = g(x) + C, where C is a constant. In particular, f (0) = g(0) + C. %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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helppp:(
![For x 2 0, prove the following identity:
| = 2 arctan vx –
arcsin
+ 1,
2
Hint:
If f,g are differentiable for x > 0 and f'(x) = g'(x), then f(x) = g(x) + C, where
C is a constant. In particular, f (0) = g(0) + C.
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b44f03f-d85c-4030-b47f-a7a76f8d7cee%2F82ae3998-1456-4984-b50d-f0be5b3adff2%2Fi1cl4s.jpeg&w=3840&q=75)
Transcribed Image Text:For x 2 0, prove the following identity:
| = 2 arctan vx –
arcsin
+ 1,
2
Hint:
If f,g are differentiable for x > 0 and f'(x) = g'(x), then f(x) = g(x) + C, where
C is a constant. In particular, f (0) = g(0) + C.
%3D
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