Will Ag2 C03 (Ksp = 8.1 250.0ml of 0.0062 m 0.00014 m Na2 Co3 are

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Chapter1: Chemical Foundations
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**Question:**

Will Ag₂CO₃ (Ksp = 8.1 x 10⁻¹²) precipitate when 250.0 mL of 0.0062 M AgNO₃ and 250.0 mL of 0.0061 M Na₂CO₃ are combined?

**Explanation:**

The given problem involves the solubility product constant (Ksp) of silver carbonate (Ag₂CO₃) and whether it will precipitate under the given conditions. 

1. **Identify the ions in solution:**
   
   - When AgNO₃ dissolves in water, it dissociates into Ag⁺ and NO₃⁻ ions.
   - When Na₂CO₃ dissolves in water, it dissociates into Na⁺ and CO₃²⁻ ions.

2. **Calculate the concentrations of ions:**

   - **For Ag⁺:**
     \[
     \text{Initial concentration of Ag⁺} = 0.0062 \, M
     \]
     When 250 mL of 0.0062 M AgNO₃ is diluted to a total volume of 500 mL:
     \[
     \text{New concentration of Ag⁺} = \frac{0.0062 \, M \times 250 \, mL}{500 \, mL} = 0.0031 \, M
     \]

   - **For CO₃²⁻:**
     \[
     \text{Initial concentration of CO₃²⁻} = 0.0061 \, M
     \]
     When 250 mL of 0.0061 M Na₂CO₃ is diluted to a total volume of 500 mL:
     \[
     \text{New concentration of CO₃²⁻} = \frac{0.0061 \, M \times 250 \, mL}{500 \, mL} = 0.00305 \, M
     \]

3. **Calculate the ion product (Qsp):**
   \[
   Q_{sp} = [Ag^+]^2 \times [CO_3^{2-}]
   \]
   Substituting the concentrations:
   \[
   Q_{sp} = (0.0031 \, M)^2 \
Transcribed Image Text:**Question:** Will Ag₂CO₃ (Ksp = 8.1 x 10⁻¹²) precipitate when 250.0 mL of 0.0062 M AgNO₃ and 250.0 mL of 0.0061 M Na₂CO₃ are combined? **Explanation:** The given problem involves the solubility product constant (Ksp) of silver carbonate (Ag₂CO₃) and whether it will precipitate under the given conditions. 1. **Identify the ions in solution:** - When AgNO₃ dissolves in water, it dissociates into Ag⁺ and NO₃⁻ ions. - When Na₂CO₃ dissolves in water, it dissociates into Na⁺ and CO₃²⁻ ions. 2. **Calculate the concentrations of ions:** - **For Ag⁺:** \[ \text{Initial concentration of Ag⁺} = 0.0062 \, M \] When 250 mL of 0.0062 M AgNO₃ is diluted to a total volume of 500 mL: \[ \text{New concentration of Ag⁺} = \frac{0.0062 \, M \times 250 \, mL}{500 \, mL} = 0.0031 \, M \] - **For CO₃²⁻:** \[ \text{Initial concentration of CO₃²⁻} = 0.0061 \, M \] When 250 mL of 0.0061 M Na₂CO₃ is diluted to a total volume of 500 mL: \[ \text{New concentration of CO₃²⁻} = \frac{0.0061 \, M \times 250 \, mL}{500 \, mL} = 0.00305 \, M \] 3. **Calculate the ion product (Qsp):** \[ Q_{sp} = [Ag^+]^2 \times [CO_3^{2-}] \] Substituting the concentrations: \[ Q_{sp} = (0.0031 \, M)^2 \
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