What volume (in L) of 1.10 M FeCl3 would be required to obtain 0.760 moles of Cl- ions?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem:**

What volume (in L) of 1.10 M FeCl₃ would be required to obtain 0.760 moles of Cl⁻ ions?

**Explanation:**

To solve this problem, we need to understand the dissociation of FeCl₃ in water. One mole of FeCl₃ dissociates into one mole of Fe³⁺ ions and three moles of Cl⁻ ions:
\[ \text{FeCl}_3 \rightarrow \text{Fe}^{3+} + 3\text{Cl}^- \]

Given the molarity of FeCl₃ solution is 1.10 M, this means there are 1.10 moles of FeCl₃ per liter of solution. Hence, 1 liter of 1.10 M FeCl₃ will produce:
\[ 1.10 \times 3 = 3.30 \text{ moles of Cl}^- \]

To find the volume that provides 0.760 moles of Cl⁻ ions, use the proportion:
\[ \text{Volume of solution} = \frac{0.760}{3.30} \text{ liters} \]

**Tools:**

The display includes a calculator interface with numbers and basic arithmetic operations for input.
Transcribed Image Text:**Problem:** What volume (in L) of 1.10 M FeCl₃ would be required to obtain 0.760 moles of Cl⁻ ions? **Explanation:** To solve this problem, we need to understand the dissociation of FeCl₃ in water. One mole of FeCl₃ dissociates into one mole of Fe³⁺ ions and three moles of Cl⁻ ions: \[ \text{FeCl}_3 \rightarrow \text{Fe}^{3+} + 3\text{Cl}^- \] Given the molarity of FeCl₃ solution is 1.10 M, this means there are 1.10 moles of FeCl₃ per liter of solution. Hence, 1 liter of 1.10 M FeCl₃ will produce: \[ 1.10 \times 3 = 3.30 \text{ moles of Cl}^- \] To find the volume that provides 0.760 moles of Cl⁻ ions, use the proportion: \[ \text{Volume of solution} = \frac{0.760}{3.30} \text{ liters} \] **Tools:** The display includes a calculator interface with numbers and basic arithmetic operations for input.
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