**Title: Determining the Mass of Iron(II) Sulfate Heptahydrate in a Sample** A powder contains FeSO₄ · 7 H₂O (molar mass = 278.01 g/mol), among other components. A 3.630 g sample of the powder was dissolved in HNO₃ and heated to convert all iron to Fe³⁺. The addition of NH₃ precipitated Fe₂O₃ · xH₂O, which was subsequently ignited to produce 0.276 g Fe₂O₃. **Question:** What was the mass of FeSO₄ · 7 H₂O in the 3.630 g sample?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Title: Determining the Mass of Iron(II) Sulfate Heptahydrate in a Sample**

A powder contains FeSO₄ · 7 H₂O (molar mass = 278.01 g/mol), among other components. A 3.630 g sample of the powder was dissolved in HNO₃ and heated to convert all iron to Fe³⁺. The addition of NH₃ precipitated Fe₂O₃ · xH₂O, which was subsequently ignited to produce 0.276 g Fe₂O₃.

**Question:**

What was the mass of FeSO₄ · 7 H₂O in the 3.630 g sample?
Transcribed Image Text:**Title: Determining the Mass of Iron(II) Sulfate Heptahydrate in a Sample** A powder contains FeSO₄ · 7 H₂O (molar mass = 278.01 g/mol), among other components. A 3.630 g sample of the powder was dissolved in HNO₃ and heated to convert all iron to Fe³⁺. The addition of NH₃ precipitated Fe₂O₃ · xH₂O, which was subsequently ignited to produce 0.276 g Fe₂O₃. **Question:** What was the mass of FeSO₄ · 7 H₂O in the 3.630 g sample?
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