width of the bar = 45 mm; thickness of the bar = 14 mm; diameter of the pin = 19 mm; yield strength of the bar material = 425 MPa; required factor of safety against yielding failure = 1.9; bearing strength of the bar material = 410 MPa; required factor of safety against bearing failure = 2.2; shear strength of the pin material = 600 MPa; and required factor of safety against shear failure = 2.3. Detrmine max allowable P
width of the bar = 45 mm; thickness of the bar = 14 mm; diameter of the pin = 19 mm; yield strength of the bar material = 425 MPa; required factor of safety against yielding failure = 1.9; bearing strength of the bar material = 410 MPa; required factor of safety against bearing failure = 2.2; shear strength of the pin material = 600 MPa; and required factor of safety against shear failure = 2.3.
Detrmine max allowable P
Given data:
Width of the bar,
Thickness of the bar: t = 14 mm
Diameter of the pin: d = 19 mm
Yield strength of the bar material:
Factor of safety against yielding failure:
Bearing strength of the bar material:
Factor of safety against bearing failure:
Shearing strength of the pin material:
Factor of safety against bearing shearing failure:
To determine the maximum allowable P, we calculate the minimum load for the failure of the connection. A connection can fail in one of the following mode:
- Yield failure of the bar
- Bearing failure of the bar
- Shearing failure of the pin
A minimum value of the above will be the maximum allowable load P.
Trending now
This is a popular solution!
Step by step
Solved in 3 steps