Why do electrons form an interference pattern when passing through a double slit? O They can not interfere, they are particles Because two slits means two beams, which will always give rise to interference Because of the uncertainty principle, the location of the electron is not exactly known when passing through the double slit, thus a single electron is interfering with itself Because different electrons go through different slits and interact because they are negatively charged
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- Electrons with an energy of 0.610 eV are incident on a double slit in which the two slits are separated by 40.0 nm. (a) What is the speed of these electrons? m/s (b) What is the de Broglie wavelength (in nanometers!) of these electrons? nm (c) What is the angle between the two second-order maxima in the resulting interference pattern?An electron is trapped in a is absorbed, the electron is in the n = 6 energy level. What was the wavelength of the absorbed photon? one-dimensional box that is 501 nm wide. Initially, it is in the n = 3 energy level but, after a photon wavelength: Eventually, the electron ends up in the ground state. As it does so, one or more photons are emitted during those transitions. Find the wavelengths of the least energetic and most energetic photons that might be emitted during all the possible transitions to the ground state. wavelength of least energetic photon: m wavelength of most energetic photon: m mA Quantum system has a ground state with energy E0 = 100meV and a 3-fold degenerate excited state with energy E1 = 100meV . Calculate the probability of finding the system in its groud state when it is at T = 300 K? a) 0.94 b) 0.06 c) 1 d) 0.98
- Electrons with a speed of 1.4×106 m/sm/s pass through a double-slit apparatus. Interference fringes are detected with a fringe spacing of 2.4 mmmm . Part A What will the fringe spacing be if the electrons are replaced by neutrons with the same speed? Express your answer in micrometers. ΔynΔyn = 1.30•10−6 μmμm SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part B What speed must neutrons have to produce interference fringes with a fringe spacing of 2.4 mmmm ? Express your answer in meters per second.Two small slits are cut 0.1 mm apart in a small piece of metal. Many electrons are fired at the slits with a speed of 300 m/s. A detector is placed 7 m away on the other side of the slits. Part A What is the smallest distance from the central maximum that the detector will not see any electrons? --ΑΣΦ • ? Submit Previous Answers Request Answer * Incorrect; Try Again; 6 attempts remaining Part B If we repeat the experiment with protons instead protons? - ΑΣΦ ^ Submit Request Answer < Return to Assignment Provide Feedback cm electrons, what is the smallest distance from the central maximum that the detector will not see any ? umElectrons with an energy of 0.842 eV are incident on a double slit in which the two slits are separated by 40.0 nm. What is the de Broglie wavelength (in nanometers!) of these electrons?
- An electron is confined between two perfectly reflecting walls separated by the distance 12 x 10-11m. Use the Heisenberg uncertainty relation to estimate the lowest energy that the particle can have (in eV).An elementary particle has a very short lifetime, 1.34 x 101 s. What is the minimum uncertainty with which we can measure its energy? Please give your answer in electron Volts.Learning Goal: To understand how to find the wavelength and diffraction patterns of electrons. An electron beam is incident on a single slit of width a. The electron beam was generated using a potential difference of magnitude V. After passing through the slit, the diffracted electrons are collected on a screen that is a distance L away from the slit. Assume that Vis small enough so that the electrons are nonrelativistic. Ultimately, you will find the width of the central maximum for the diffraction pattern. Part B What is the wavelength of the electron beam? Use the de Broglie relation and the momentum that you found in Part A. Express your answer in terms of h, me, e, and V. X = [5] ΑΣΦ Submit Request Answer ?