While we are at it, let's do the same thing for the second step of the mechanism. Again, what is happening with the arrows circled in red below? Cys157 Cys157 Cys157 His296 His296 His296 OH HO HO HN, HN, HN Co2 Asn329 Asn329- Asn329- Cys157 His296 он „OH HNNH Asn329 O deprotonation of the conjugate acid form of imidazole, followed by general base assistance in decarboxylation nucleophilic addition of the cysteine side chain to imidazole O decarboxylation coupled with the generation of molecular hydrogen (H2) O general acid catalyzed isomerization covalent attachment of the substrate to the enzyme

While we are at it, let's do the same thing for the second step of the mechanism. Again, what is happening with the arrows circled in red below? Cys157 Cys157 Cys157 His296 His296 His296 OH HO HO HN, HN, HN Co2 Asn329 Asn329- Asn329- Cys157 His296 он „OH HNNH Asn329 O deprotonation of the conjugate acid form of imidazole, followed by general base assistance in decarboxylation nucleophilic addition of the cysteine side chain to imidazole O decarboxylation coupled with the generation of molecular hydrogen (H2) O general acid catalyzed isomerization covalent attachment of the substrate to the enzyme

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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9. Which of the following is the rate-determining step in the free-radical bromination of methane? I II III IV V A) I B) II C) III D) IV E) V Br₂ CH4 CH3 CH4 CH3 + Br Br₂ Br CH3 2 Br CH3Br + H CH3Br + CH3 CH3CH3 Br HBr
How many sigma electrons are there in the alkene in "Figure 15" below? A 12 Or TOH Possible reasons why this elementary step is unlikely: AH-Br bond must break towards the bromine atom. The hydroxide ion will not react with the electron rich part of the molecule. The hydrogen atom cannot accommodate two electrons. 087 OC2 OD. 6 HOBr H
Could you show the mechanism for Question 2, parts A-D?
Can i get help with this please
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人工知能を使用せず、すべてを段階的にデジタル形式で解決してください。ありがとう SOLVE STEP BY STEP IN DIGITAL FORMAT DON'T USE CHATGPT 3.- Provide the products of each reaction and say what type of product it corresponds to (SN1 or SN2). As well as the reaction mechanism from which they are formed. ゾ Br Na CN CH3CH2OH Na OCH₂CH3 EtOH
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Hint 13.18c3 Add curved arrow(s) to draw the final step of the mechanism. H3C- :OH + CH3 :OH 98. an-ak CH3 CH3 Save for Later CH3 Edit Drawing CH3 :ÖH CH3
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3. Br, will react with the previously formed benzylic radical, affording the reaction product and a Br radical, which permits the reaction to go on (propagation): COOH СООН + Br-Br Br ÇH2 Br 4. Lastly, various radicals may react with each other, "quenching" or ending the radical cascade. Suggest below possible termination steps:
но, CH, CHO CHO Drag the appropriate labels to their respective targets. Reset Help I equivalent acid catalyst - H;0 ether H,O CH,OH CH,MgBr но OH HO CH, CHO CHO