While two forces act on it, a particle is to move at the constant velocity = (3 m/s) i of the forces is 7₁ = (2 N) Î + (−6 N) ĵ. What is the other force? (4 m/s) ĵ. One
Q: A runner of mass 62.0 kg initially moves at a
A:
Q: A bowling ball weighing 61.5 N initially moves at a speed of 4.00 m/s. How long must a force of 42.5…
A:
Q: Three forces act on a particle that moves with unchanging velocity (2.4 m/s )i + (-6.5 m/s )j. Two…
A:
Q: Again, m = mass of projectile = 0.045 kg, k Spring constant of launcher = 100 N/m, and x the spring…
A: The spring constant k = 100 N/m The mass of the projectile m = 0.045 kg Distance the spring is…
Q: An object with mass m = 34 kg is pushed with 452 N of force to be moved across a distance of 4.6 m…
A: Given data: The mass is m=34 kg The applied force is F=452 N The displacement is s=4.6 m The…
Q: 48. John fires a projectile in a Uwindsor lab and notes that the 20.0g projectile travels 785 m/s.…
A: John fire a projectile and note that the20 gram projectile penentrate the clay ball. We need to find…
Q: A parachutist whose mass is 65 kg drops from a helicopter hovering 2500 m above the ground and falls…
A: Given Data:Mass of the person Height of the helicopter The proportionality constant when the…
Q: pass by. you fnying horizontally at a height of h = 21.95 m. When the swallow is directly overhead,…
A:
Q: What is the direction of the net force, expressed as an angle in degrees measured clockwise relative…
A:
Q: Tarzan swings on a 39.0 m long vine initially inclined at an angle of 42.0° with the vertical. The…
A:
Q: A force F= (-2Nm)xi+(4Nm2)x2j-8Nk and a second force F=(-4Nm2)x2j-8Nk are applied to a 4 kg object…
A: A force F= (-2Nm)xi+(4Nm2)x2j-8Nk and a second force F=(-4Nm2)x2j-8Nk are applied to a 4 kg object…
Q: A horizontal force of magnitude F = 57.5 N pushes on a block of mass m = 4.7 kg. The block is on a…
A: The given situation can be represented as
Q: A small boat is crossing a lake on a windy day. During some interval of time, the boat undergoes the…
A: ∆r⇀ = 3.19 i⏜ + 2.89 j ⏜F→ = 261 i⏜ - 125 j⏜
Q: The football's initial velocity comp ir resistance and any other noncon
A: The initial height of football, x-component of an initial velocity,…
Q: roblem 10: While watching the clouds pass by, you notice a European swallow flying ally at a height…
A: Motion of projectile can be divided into x component and y component.
Q: A constant applied force ?pFp of 15.0 N15.0 N pushes a box with a mass ?=7.00 kgm=7.00 kg a distance…
A:
Q: ➜ 1 ✰ 0 https://mapleton.instructure.com/courses/16703/assignments/300550 4 1 1 point A 1kg flower…
A:
Q: 18.710 7. An airplane of mass 1.5x104 kg moves horizontally at a speed of 60.0 m/s. The pilot then…
A:
Q: is the final speed?
A:
Q: Two constant forces act on an object of mass m - 4.30 kg object moving in the xy plane as shown in…
A: Hey, since there is multiple subpart question posted, we will answer first three questions. If you…
Q: Two constant forces F1 = 8.5 "i +5.6 *j +8.4^ k N and F2 = %3D 1.7^i -3.5 *j -4.7^k N act together…
A:
Q: The wow expert Hand written solution is not allowed.
A: The momentum before pushing the carts is zero since they are stationary. After pushing, the momentum…
Q: 10. I wish to tow a 53 kg load (3 children plus a toboggan) up a snowy hill for a toboggan run,…
A: This is a question regarding the motion of a body under a combination of forces. The motion of the…
Q: A block with mass m = 14.9 kg slides down an inclined plane of slope angle 18.8o with a constant…
A: Consider the free-body diagram of the block when it slides down the incline with a constant velocity…
Q: Compressed air is used to fire a 46.0 g ball vertically upward from a 1.8-m-tall tube. The air…
A:
Q: Three forces act on a particle that moves with unchanging velocity V = (2.2 m/s)i + (-7.8 m/s)j. Two…
A: Since v is constant, acceleration is zero. Fnet=ma =mdvdt =m0 =0…
Q: An object with a mass of 1.53 kg is initially at rest upon a horizontal, frictionless surface. An…
A: Mass of an object is,m= 1.53 kgThe object is initially at rest,vi = 0The applied force is,F =4.94…
Q: Two horizontal forces, P and Q, are acting on a block that is placed on a table. We know that P =…
A: Given: The mass of the object is 5.1 kg. P→=-2.1i^+4.25k^ N The velocity of the object is constant.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
- A parachutist whose mass is 60 kg drops from a helicopter hovering 1000 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b₁ = 20 N-sec/m when the chute is closed and b2 = 90 N-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 25 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec². The parachutist will reach the ground after (Round to two decimal places as needed.) seconds.Asap please.....Problem 5: Consider the vectors, D = (6.00î - 8.00j) m, B = (-8.00î + 3.00j) m, and A = (26.0î + 19.0j) m.
- A box of mass 21 kg moves with a constant velocity of (4, 8, –4) m/s. Three forces are exerted on the box by objects in the surroundings. Two of these forces are F 1 = (1,0, 3) Nand É 2 = (-5, –1, 19) N. What is the third force? F3 = ( i ! )N i iA parachutist whose mass is 70 kg drops from a helicopter hovering 2500 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b₁ = 30 N-sec/m when the chute is closed and b₂ = 90 N-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 15 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec². - The parachutist will reach the ground after (Round to two decimal places as needed.) * seconds.DETAILS PREVIOUS ANSWERS SERPSE10 7.4.P.016. MY NOTES ASK YOUR TEACHER The force acting on a particle is F, = (10x – 17) N, where x is in meters. (a) Make a plot of this force versus x from x = 0 to x = 3.00 m. F (N) F (N) 50 20 40 10 3어 20 0,5 1.0 15 20 2,5 x (m) 30 10 -10 x (m) 3.0 0.5 1.0 1.5 2.0 2.5 F (N) F (N) 0,5 1.0 + x (m) 2,5 30 1아 1.5 2,0 -1어 2,5 x (m) 30 -20 0,5 1,0 15 -30 -10 - 40 -20 - 50 (b) From your graph, find the net work done by this force on the particle as x = 0 to x = 2.55 m. (Include the correct sign.) it moves from Need Help? Read It
- Besides the gravitational force, a 2.90-kg object is subjected to one other constant force. The object starts from rest and in 1.20 s experiences a displacement of (4.30î − 3.30ĵ) m, where the direction of ĵ is the upward vertical direction. Determine the other force. (Express your answer in vector form.)If you have a ball with a mass of 6.00kg, that has an initial velocity of vA=(2.00i + 5.00j)m/s and a final velocity of vB=(-2.00i + 8.00j)m/s, What is the change in velocity in unit vector format? a. -4.00i + 3.00j b. -2.83i + 3.61j c. 4.00i – 3.00j d. 0.00i + 13.0jIn (Figure 1), F={300i-100j+550k}NF= (300i-100j+550k)N. Determine the magnitude of the projection of the force FF acting along the cable BA◆◆. Express your answer to three significant figures and include the appropriate units. Figure 2m 6m 1 of 1 3m