sadasdasdasdas 10. I wish to tow a 53 kg load (3 children plus a toboggan) up a snowy hill for a toboggan run, climbing the hill at aconstant velocity of 0.73 m/s up the gentle 10 degree incline. I pull the toboggan with a length of rope at a 30degree angle as shown. The coefficients of friction are given between the snow and the toboggan.(μ=0.09, μ,-0.11).a) Draw a free body diagram of the forces acting on the load during the assent.b) Find the tension in the rope.c) Once at the top we turn it around and do a run. I also get on the toboggan adding an additional 80kg to the load. Find our velocity once we go 80 meters down the hill given an initial speed of 3 m/s from apush off at the top.

Answered: 10. I wish to tow a 53 kg load (3…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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sadasdasdasdas

10. I wish to tow a 53 kg load (3 children plus a toboggan) up a snowy hill for a toboggan run, climbing the hill at a
constant velocity of 0.73 m/s up the gentle 10 degree incline. I pull the toboggan with a length of rope at a 30
degree angle as shown. The coefficients of friction are given between the snow and the toboggan.
(μ=0.09, μ,-0.11).
a) Draw a free body diagram of the forces acting on the load during the assent.
b) Find the tension in the rope.
c) Once at the top we turn it around and do a run. I also get on the toboggan adding an additional 80
kg to the load. Find our velocity once we go 80 meters down the hill given an initial speed of 3 m/s from a
push off at the top.

Expert Solution

Step 1

This is a question regarding the motion of a body under a combination of forces.

The motion of the body is in two-dimensions. Hence, the forces must be split into their constituent vertical and horizontal components.

The frictional force acting on a body is given by the relation:
$f = μ N$
where,
$μ$ is the coefficient of friction and
N is the normal force acting on the body.

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