DETAILS PREVIOUS ANSWERS SERPSE10 7.4.P.016. MY NOTES ASK YOUR TEACHER The force acting on a particle is F, = (10x – 17) N, where x is in meters. (a) Make a plot of this force versus x from x = 0 to x = 3.00 m. F (N) F (N) 50 20 40 10 3어 20 0,5 1.0 15 20 2,5 x (m) 30 10 -10 x (m) 3.0 0.5 1.0 1.5 2.0 2.5 F (N) F (N) 0,5 1.0 + x (m) 2,5 30 1아 1.5 2,0 -1어 2,5 x (m) 30 -20 0,5 1,0 15 -30 -10 - 40 -20 - 50 (b) From your graph, find the net work done by this force on the particle as x = 0 to x = 2.55 m. (Include the correct sign.) it moves from Need Help? Read It
DETAILS PREVIOUS ANSWERS SERPSE10 7.4.P.016. MY NOTES ASK YOUR TEACHER The force acting on a particle is F, = (10x – 17) N, where x is in meters. (a) Make a plot of this force versus x from x = 0 to x = 3.00 m. F (N) F (N) 50 20 40 10 3어 20 0,5 1.0 15 20 2,5 x (m) 30 10 -10 x (m) 3.0 0.5 1.0 1.5 2.0 2.5 F (N) F (N) 0,5 1.0 + x (m) 2,5 30 1아 1.5 2,0 -1어 2,5 x (m) 30 -20 0,5 1,0 15 -30 -10 - 40 -20 - 50 (b) From your graph, find the net work done by this force on the particle as x = 0 to x = 2.55 m. (Include the correct sign.) it moves from Need Help? Read It
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![DETAILS
PREVIOUS ANSWERS
SERPSE10 7.4.P.016.
MY NOTES
ASK YOUR TEACHER
The force acting on a particle is F,
= (10x – 17) N, where x is in meters.
(a) Make a plot of this force versus x from x = 0 to x = 3.00 m.
F (N)
F (N)
50
20
40
10
3어
20
0,5
1.0
15
20
2,5
x (m)
30
10
-10
x (m)
3.0
0.5
1.0
1.5
2.0
2.5
F (N)
F (N)
0,5
1.0
+ x (m)
2,5
30
1아
1.5
2,0
-1어
2,5
x (m)
30
-20
0,5
1,0
15
-30
-10
- 40
-20
- 50
(b) From your graph, find the net work done by this force on the particle as
x = 0 to x = 2.55 m. (Include the correct sign.)
it moves from
Need Help?
Read It](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff0934709-0504-48f9-9892-049f7d0817f7%2Fe5fd1c35-7ed0-47d9-9b7b-130bcd186027%2Fviihs3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:DETAILS
PREVIOUS ANSWERS
SERPSE10 7.4.P.016.
MY NOTES
ASK YOUR TEACHER
The force acting on a particle is F,
= (10x – 17) N, where x is in meters.
(a) Make a plot of this force versus x from x = 0 to x = 3.00 m.
F (N)
F (N)
50
20
40
10
3어
20
0,5
1.0
15
20
2,5
x (m)
30
10
-10
x (m)
3.0
0.5
1.0
1.5
2.0
2.5
F (N)
F (N)
0,5
1.0
+ x (m)
2,5
30
1아
1.5
2,0
-1어
2,5
x (m)
30
-20
0,5
1,0
15
-30
-10
- 40
-20
- 50
(b) From your graph, find the net work done by this force on the particle as
x = 0 to x = 2.55 m. (Include the correct sign.)
it moves from
Need Help?
Read It
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