Which statement best characterizes the following reaction of 2-phenylpropan-2-ol with HBr? OH CH3 CH3 + HBr Br CH3 CH3 + H₂O It is an SN1 reaction with bromide as the nucleophile and water as the leaving group. It is an SN1 reaction with HBr as the nucleophile and hydroxide ion (HO-) as the leaving group. It is a one step concerted reaction with bromide as the nucleophile and hydroxide ion (HO-) as the leaving group. It is an SN2 reaction with bromide as the nucleophile and water as the leaving group.

Which statement best characterizes the following reaction of 2-phenylpropan-2-ol with HBr? OH CH3 CH3 + HBr Br CH3 CH3 + H₂O It is an SN1 reaction with bromide as the nucleophile and water as the leaving group. It is an SN1 reaction with HBr as the nucleophile and hydroxide ion (HO-) as the leaving group. It is a one step concerted reaction with bromide as the nucleophile and hydroxide ion (HO-) as the leaving group. It is an SN2 reaction with bromide as the nucleophile and water as the leaving group.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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11) The SN2 reaction of iodocyclopropane with sodium methylmercaptide (CH3SNA) is not observed. Why? X- H + CH3SNA + Nal SCH3 A) iodide, generally, is not a good leaving group B) the cyclopropane ring sterically hinders the reaction pathway C) sulfur anions, generally, are not good nucleophiles D) the required hybridization change at the transition state causes too much strain E) the sulfur anion is too large
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Why is a strong acid (like HCI) used in a Grignard reaction? O 1) A strong acid is used in the Grignar reaction in order to protonate the carbonyl in order to make a better leaving group, OH. Once teh OH leaves, the alcohol group is reformed due to water. A stable tetrahedral intermediate with a negatively charged oxygen forms O 2) that does not possess a leaving group. This intermediate will exist until a proton source from the strong acid protonates the negatively charged oxygen, affording the neutral alcohol product. 3) The use of a strong acid is not necessary. It is simply recommended as it increases the yield produced in the reaction. 4) The use of a strong acid is necessary for the formation of a Grignard reagent. Without a strong acid, the organomagnesium compound cannot be formed.