Which sequence correctly ranks the following aromatic rings in order of increasing rate of reactivity in an electrophilic aromatic substitution reaction? CH₂ 2<1<3 2<3 <1 3<1<2 1<2<3 2 .CH₂ OCH₂
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ORG. CHEM THE ANSWER IS NOT 1<2<3
![Which sequence correctly ranks the following aromatic rings in order of increasing rate of
reactivity in an electrophilic aromatic substitution reaction?
CH₂
2<1<3
2 < 3 < 1
3 < 1 < 2
1<2<3
2
.CH₂
3
OCH3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd89afd29-6360-428c-829c-e06d8f056871%2F5d9c8ba5-f4fd-4735-874a-b670257cdf45%2F6s1wfq3_processed.png&w=3840&q=75)
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- For following substituted benzenes: [1] C6H5Br; [2] C6H5CN; [3] C6H5OCOCH3: Does the substituent activate or deactivate the benzene ring inelectrophilic aromatic substitution?Which reagent is the nucleophile in the esterification reaction shown below? O || С-ОН Benzoic Acid methanol methyl benzoate benzoic acid sulfuric acid + CH₂-OH Methanol H₂SO - H₂O O || C-O-CH3 Methyl benzoateQB. In the following compounds identify, with an arrow, the position that is most reactive towards electrophilic aromatic substitution. LOCH₁ ∞∞ da of OH O₂N- OCH,
- O In this step alkyne anion is alting and it is attacking cecting acting as 4 electrophile a Pla وعك Ho as a nucleophile on the genen molecule, which is Br pom 산 2-Bromo propane (26105 576 honros он 2The given reaction scheme is an example of which type of reaction? O || R₁-C-OH + R₂-OH Oxidation Fischer esterification Nucleophilic substitution Reduction Rearrangement reaction Acid O || R₁-C-O-R₂ Meeting in "General"In EAS bromination reactions, a -NHCOCH3 substituent on the aromatic ring is: O an activator and an o,p-director. O a deactivator and a m-director. an activator and a m-director. NHCOCH3 catalyzes the 1,2 addition of bromine across the double bond O a deactivator and an o,p-director.
- Which of the following is NOT a correct statement about the electrophilic aromatic substitution mechanism? Benzene functions as a nucleophile. Aromaticity is regained by loss of H*. Formation of a carbocation intermediate is the rate-determining step. The carbocation intermediate contains an sp° hybridized carbon in the ring. O The addition product is a frequent minor product.can you explain how can we determine major and minor product from these reaction elimination-addition? &=&=1561=6, NH₂ majo CH, NH₂ NH₂ &=-&-&-& majo CH3 OCH, CI NINH, NH 3liq. KNH₂ NH309. Br ΚΝΗ, NH CI CH₁ 80 80 OCH, majo NH, NH₂ mino CH3 mino NH₂ NH₂ NH, NH, CI majo CH3 majo NH₂ NH₂What is the product of the following sequence of reactions? D | NaOH NaNH2 H3O+ || ||| explain each steps..explanation needed. don't give Handwritten answer IV NH₂
- Determine the mechanism of nucleophilic substitution of each reaction and draw the products, including stereochemistr CH₂CH3 CI Br + CN d. + CH3COOH a. acetone + -OCH3 e. DMF f. b. C. ||||| a ||||| Br H Br CH2CH2CH3 + CH3OH DMSO H CH3 CI Br + OCH₂CH3 + CH3CH₂OHP Problem 35 of 44 Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. HH دته CI HH heat H |||||| Select to Add Arrows NaNH2, THF Na O O CI O Na → Submitb) Listed below are several hypothetical nucleophilic substitution reactions. None is synthetically useful because the product indicated is not formed at an appreciable rate. In each case provide an explanation for the failure of the reaction to take place as indicated. OMe HO + OMe + OH HO + CH; OH
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