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- 3:43 ll LTE O moellim.riphah.edu.pk Biochemistry-l Dashboard / My courses / Biochemistry-II | General / QUIZ 1 Question 7 Not yet answered Marked out of 1.00 P Flag question ADP will the regulatory enzymes of TCA cycle? Select one: O a. None O b. Both depending on condition O c. Inhibit O d. Activate Next page Course OutlinePlease help with part a and b both the questions urgently within an hourAA View Tell me Convert to SmartArt W- Picture Shapes - Text Box Arrange Quick d Tue Dec 6 3:13 PM ♫ Share Design Qsn 2 (a) A pathway consists of 6 enzymes (p, q, r, s, t, u) that convert substrate J to product X at a rate of 10 moles/hour. If enzyme q is increased from 5 mmoles to 35 mmoles the amount of product X increases to 20.5 moles/hour. What is the flux control coefficient for enzyme q (C¹)?
- Part 1: Assess the following partial results section below by editing it for brevity by omitting any unnecessary parts (1 point), explain why you decided to remove certain sections (1 point): To evaluate inhibitory effects of the selected molecules, 10mM stock solutions of each molecule were prepared in DMSO. A reaction mixture (200μl) was prepared with the same formula optimized for the enzyme activity assay (0.1 M Tris-HCl ph 8, 0.1 M KCI, 25 mM NaCl, 0.25 mM ATP, and two units of inorganic yeast pyrophosphatase) with 10 µM of the sample molecule. The reaction mixture was incubated for 20 minutes at ambient temperature. Enzymatic reaction was triggered by addition of the substrate B (0.2 mM) and the absorbance of the product was monitored at 290 nm for 10 minutes. Six out of 15 sample molecules showed appreciable inhibition at 10 μM (Figure 5). Three of the molecules, A3, A6, and A7 exhibited more than 50% inhibition of the enzyme activity and were further diluted to find the minimal…National Board of Medical Examiners Biochemistry Mark 36. In the presence of a metabolite (X), 6-phosphofructokinase is assayed at a fixed concentration of ATP and varying concentrations of fructose 6-phosphate. The resulting data are shown in the table. Fructose 6-phosphate (pM) 5 10 20 40 75 100 200 Velocity umoles/min 0.05 0.15 0.25 0.70 1.7 2.2 3.1 3.1 Velocity (+X) umoles/min 0.006 0.025 0. 10 0.35 1.03 16 2.9 3.1 400 Metabolite (X) is most likely which of the following substances? O A) ADP O B) AMP OC) CAMP D) Citric acid O E) Fructose-2,6-bisphosphatePTP1B Substrate kcat Km. kcat/Km UM 10-7 x (s-1 M) DADEPYLIPQQG DADAPYLIPQQG DAAEP YLIPQQG AAAAPYLIPQQG 44.6 + 1.8 39.8 + 0.32 3.9 + 0.9 13.7 + 0.46 1.1 + 0.25 0.29 + 0.01 35.3 + 0.22 6.6 + 0.22 0.53 + 0.02 34.7 + 0.25 52.7 + 0.7 0.066 + 0.001 ) The units for kcat/KM in the above are given according to standard scientific notation. On this (d) ( basis what is the value of this kinetic parameter for the DADEPYLIPQQG substrate?
- for the table just do the results and discussion for phosphatw. Table 2. Presence of Nucleic Acid Hydrolysis Products in DNA Hydrolysate Component Tested Diagnosis (+/-) Purine Bases Ribose Deoxyribose Phosphate Sample DNA test solution Distilled water DNA test solution 1% ribose 1% glucose DNA test solution 1% ribose 1% glucose DNA test solution 1% ribose 1% glucose for the photos: use it for the DNA extractiom results. Glucose Below. results during the experiment 8. Test for phosphate on the DNA hydrolysate Sample DNA hydrolysate Ribose Observations (describe what happened) From clear white to light yellow with white precipitate From clear white to cloudy white and no formation of precipitate. From clear white to pale yellow and no formation of precipitate. Diagnosis (Positive/Negative?) 1. Observations on the extraction of DNA Write your observations on the space below. (no sentence limit) If you have photographs, attach them at the end of the document. The blended frozen peas were…CHEM151/251 Biochemistry 1 a. Determine Km 1. The following data were obtained for a competitive inhibition study in which the [I] = 3 µM for each determination of vo in the presence of inhibitor. The Vmax = 200 μM P/min for both data sets. 200 Vo (UM P/min) 8 8 8 8 8 8 8 8 8 180 160 140 120 100 40 Name (Print)/ID #: the absence of inhibitor. Participation Question # 10 No Inhibitor 50 +Inhibitor 100 [Substrate] (UM) 150 b. Determine Km, app for the data obtained in presence of inhibitor. 200 c. Calculate the value for Ki. Note: a = 1 + [I]/Ki and a¹ = 1 + [I]/Ki*. for the data obtained inpluginfile.php/7382296/mod_resource/content/0/Purine%20Practice%20Pathway.pdf 1 / 1 67% Purine * Know regulatory steps Synthesis *Know how GTP and ATP control production O D-O O-0 R-5 P 5-phosphoribas ylamine EZ 9 oteps IMP ロロ AMP GMP E3 ES E7 LADP E4 Eb ATP JATP GTP typ