Which one of the following statements is incorrect:A. A type I error consists of rejecting the null hypothesis when it is trueB. A type II error consists of accepting the null hypothesis when it is falseC. You can control simultaneously both the Type I and Type II error probabilitieswhen the sample size is fixedD. Hypothesis testing and confidence intervals are related conceptsAсBD

From the given statements select the incorrect

Answered: Which one of the following statements…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the mean GPA of night students is larger than 2 at the 0.10 significance level. The null and alternative hypothesis would be: Họ :p = 0.5 Họ:µ = 2 Ho:u 0.5 Ho:p 2 H1 :p + 0.5 H1:µ # 2 H1:µ > 2 H1:p 0.5 H1:µ < 2 The test is: left-tailed right-tailed two-tailed Based on a sample of 25 people, the sample mean GPA was 2.02 with a standard deviation of 0.05 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Large Sample Proportion Problem. Surveys were conducted in multiple countries and respondents were asked if they felt political news was reported fairly. The data for the United States is that out of 1,000 sampled, 470 indicated yes, they felt political news was reported fairly. Suppose we construct a 99% confidence interval and the upper and lower bounds are .4293 to .5107. What can I conclude about a two-tailed hypothesis test where Ho: P=.5 and alpha is .01? I don't have enough information to make a conclusion. I would fail to reject the Null Hypothesis that P = .5 I would be able to reject the Null Hypothesis that P=.5, but only for a one-tailed test. I would be able to reject the Null Hypothesis that P = .5
Test the claim that the proportion of people who own a pet is smaller than 50% at the 0.05 significance level. The null and alternative hypothesis would be: Но: р 3 0.5 Но:д > 0.5 Но:д 0.5 Ні:р 0.5 Hi:р + 0.5 The test is: left-tailed two-tailed right-tailed Based on a sample of 600 people, 288 owned a pet, the p-value is: |(to 4 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the mean GPA of night students is smaller than 2.2 at the 0.025 significance level. The null and alternative hypothesis would be: Ho: 2.2 Ho:p ≤ 0.55 Ho:p≥ 0.55 Ho:p = 0.55 Ho:μ = 2.2 Ho:μ ≤ 2.2 H₁: 0.55 H₁:p 2.2 The test is: two-tailed left-tailed right-tailed Based on a sample of 35 people, the sample mean GPA was 2.15 with a standard deviation of 0.04 The p-value is: Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis (to 2 decimals)
Test the claim that the mean GPA of night students is larger than 3.1 at the 0.01 significance level. The null and alternative hypothesis would be: Но: р — 0.775 Но:р> 0.775 Но: и — 3.1 Но:р 3.1 Н:р+ 0.775 Hi:р 3.1 H]:p > 0.775 Hi:р < 3.1 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.14 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is larger than 20% at the .05 significance level. The null and alternative hypothesis would be: 0.2 Но:р — 0.2 Но: и 0.2 Ho:H Ho:H H:р + 0.2 Н]:р 0.2 Hi:р > 0.2 Hi:р#0.2 0.2 Но:р || The test is: left-tailed two-tailed right-tailed Based on a sample of 25 people, 25% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Which one of the following statements is incorrect: A. A type I error consists of rejecting the null hypothesis when it is true B. A type II error consists of accepting the null hypothesis when it is false C. You can control simultaneously both the Type I and Type II error probabilities when the sample size is fixed D. Hypothesis testing and confidence intervals are related concepts
Test the claim that the mean GPA of night students is significantly different than 2 at the 0.01 significance level. The null and alternative hypothesis would be: Но: р > 0.5 Нo: 2 H1:p > 0.5 H1:µ # 2 H1:p+ 0.5 H1:µ 2 The test is: right-tailed left-tailed two-tailed Based on a sample of 55 people, the sample mean GPA was 2.05 with a standard deviation of 0.03 The p-value is: (to 2 decimals)
Test the claim that the proportion of people who own cats is larger than 20% at the 0.005 significance level. The null and alternative hypothesis would be: H2:p = 0.2 Họ:p 2 0.2 H9:p 0.2 H9:p = 0.2 Hg: u 0.2 H1: u 0.2 The test is: left-tailed two-tailed right-tailed Based on a sample of 300 people, 24% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.05 significance level. The null and alternative hypothesis would be: Ho: PNPD Ho: UN ≤ HD Ha:N HD Ha:μN > HD The test is: right-tailed two-tailed left-tailed O Ho: PNPD Ho: PNPD Ho: PN Ha:PN PD O
Test the claim that the mean GPA of night students is significantly different than 2.5 at the 0.1 significance level. The null and alternative hypothesis would be: Ho: µ 2 2.5 Ho:p 0.625 Ho:p= 0.625 Ho: µ 0.625 H1:p 2.5 H:µ + 2.5 The test is: left-tailed two-tailed right-tailed Based on a sample of 60 people, the sample mean GPA was 2.47 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
4. An app developer would like to know how many songs people put in their phones. He interviewed 25 of them and found that they have 34.5 songs on average with a sample standard deviation of 3.4 songs. With a confidence level of 90%, determine the confidence interval estimate of the population mean.

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