Test the claim that the mean GPA of night students is significantly different than 2 at the 0.01 significance level. The null and alternative hypothesis would be: H,:µ = 2 H,:µ < 2 Ho:p=0.5 Ho:p > 0.5 Ho:µ > 2 H,:p< 0.5 H:µ +2 H:µ > 2 Hj:p+0.5 H,:p< 0.5 H,:µ< 2 H:p> 0.5 The test is: left-tailed right-tailed two-tailed Based on a sample of 75 people, the sample mean GPA was 2.03 with a standard deviation of 0.08 The test statistic is: |(to 2 decimals) The p-value is: |(to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.

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