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- The measured density of a CsCl crystal is 3.988 g/cm3. What is the equilibrium separate distance of Cs+ and Cl- ions?For the following cases, what type of bonding expected? (a) KCl molecule; (b) N2 molecule.Define the following terms: (i) Single Crystalline, Polycrystalline and Amorphous materials, (ii) Lattice, basis and crystal structure,(iii) Bravais lattice. Distinguish between the coordination number and the number of atoms per unit cell. Find both these numbers for a simple cubic lattice, a body centered cubic lattice and a face centered cubic lattice. (a)
- Hcp structure. Show that the cla ratio for an ideal hexagonal close-packed strue- ture is 2 = 1.633. If cla is significantly larger than this value, the crystal structure be thought of as composed of planes of closely packed atoms, the planes being loosely stacked. %3D mayThe ionic crystal of NaCl has an fcc structure as shown below with the position of the Cl atom located at : (0 0 0); (½ ½ 0); ( ½ 0 %) and (0 ½) and Na atom is located at : (½ ½½) + fcc translation. The following are the physical data of NaCl: - Ionic radius Na = 0.98 A, Cl ion radius 1.81 A Atomic mass of Na = 22.99 amu, Atomic mass of Cl = 35.45 amu NaCl bulk modulus = 2.40 x 1010 N/m - Madelung's constant = 1.75 Young's modulus in the direction [100] = 5 x 1010 Nm-2 Debye temperature = 281 K - State the structural factors of NaCl, F in fNa and fCl (f = atomic scattering factor). Also determine the condition (h k 1) so that the value of F = 0.At 23° K, the crystal structure transforms from BCC to HCP keeping density same. The cubic face in BCC is a 3.42 A and in HCP is-1.53. The lattice constant in HCP structure is, (n) 2.64 A (b) 3.16 A () 2.16 A (4) 2.42 A
- In solid KCI the smallest distance between the centers of a. potassium ion and a chloride ion is 314 pm. Calculate the length of the edge of the unit cell and the density of KCI, assuming it has the same structure as sodium chloride.The parameters o and & in Lennard-Jones potential in Argon (Ar) crystals are o = 3.40 x 10-10 m and ɛ = 1.67 x 10-21 J. The lattice sums for the BCC (body-centered cubic) structures are E C" Pī12 = 9.11418, ECC Pī = 12.2533, and the lattice sums for the FCC structures are 2CC Pī12 = potential, calculate the equilibrium separation and cohesive energies (in unit of electron voltage or eV) for BCC and FCC configurations. -6 %3| 12.13188, ECC Pi = 14.45392. Using the Lennard-Jones %3DThe atomic radius of an iron atom is (1.238 nm). Iron crystallizes as BCC. Calculate the: 1- lattice parameter of the unit cell, 2- How many atoms are contained within the BCC unit cell
- At 23° K, the crystal structure transforms from BCC to HCP keeping density same. The cubic face in BCC is a= 3.42 A and in HCP is = 1.53. The lattice constant in HCP structure is, (а) 2.64 A (b) 3.16 А (c) 2.16 A (d) 2.42 AFor the cubic NaCl structure, shown in the figure, (a) calculate the reciprocal space translations vectors, and (b) write down the lattice type of this reciprocal lattice. Na+ CrQuestion A2 The body-centred cubic structure is common among metals. a) How many nearest neighbours has each atom in this structure? Give the nearest-neighbour distance in terms of the unit cell parameter a. b) How many second-nearest neighbours has each atom in this structure? Give the second- nearest-neighbour distance in terms of the unit cell parameter a. c) How many third-nearest neighbours has each atom in this structure? Give the third-nearest- neighbour distance in terms of the unit cell parameter a.
