Which one of the following complexes has a spin of S = 2? %3D A. trans-Ni(H2O)4CI2 B. [Co(CN)6]3- C. fac-[FeCl3Br3]4- D. A-[Mn(en)3]2+

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### Spin State Question on Coordination Complexes

**Question:**
Which one of the following complexes has a spin of S = 2?

**Options:**
A. *trans*-Ni(H₂O)₄Cl₂  
B. [Co(CN)₆]³⁻  
C. *fac*-[FeCl₃Br₃]⁴⁻  
D. Δ-[Mn(en)₃]²⁺

#### Explanation and Solution:

To determine the spin state (S = 2) of a coordination complex, one must consider the electronic configuration and ligands of the central metal ion. The spin state is influenced by the number of unpaired electrons in the d-orbital.

1. **Option A: *trans*-Ni(H₂O)₄Cl₂**
   - Central metal: Ni (Nickel)
   - Oxidation state and electron configuration need to be determined.

2. **Option B: [Co(CN)₆]³⁻**
   - Central metal: Co (Cobalt)
   - Known to form low-spin complexes with strong field ligands like CN⁻.

3. **Option C: *fac*-[FeCl₃Br₃]⁴⁻**
   - Central metal: Fe (Iron)
   - Mixed halide ligands wit\( \h getting the specific coordination geometry.

4. **Option D: Δ-[Mn(en)₃]²⁺**
   - Central metal: Mn (Manganese)
   -  En stands for ethylenediamine, a bidentate ligand that typically forms high-spin complexes.
   
The goal is to identify the complex with a total spin \( \text{S} = 2 \), corresponding to having 4 unpaired electrons. The key is to understand the high-spin or low-spin nature of each complex, given the crystal field splitting and the nature of the ligands.

**Graph Explanation:**

This problem does not include graphs or diagrams, but a common way to solve such questions involves the use of crystal field splitting diagrams, which visually demonstrate the arrangement of electrons in the high-spin or low-spin states depending on the ligand field strength.

By applying the crystal field theory and analyzing the options, one can determine which complex fits the criteria of having 4 unpaired electrons, leading to a spin state \( \text{S} = 2 \). 

Detailed
Transcribed Image Text:### Spin State Question on Coordination Complexes **Question:** Which one of the following complexes has a spin of S = 2? **Options:** A. *trans*-Ni(H₂O)₄Cl₂ B. [Co(CN)₆]³⁻ C. *fac*-[FeCl₃Br₃]⁴⁻ D. Δ-[Mn(en)₃]²⁺ #### Explanation and Solution: To determine the spin state (S = 2) of a coordination complex, one must consider the electronic configuration and ligands of the central metal ion. The spin state is influenced by the number of unpaired electrons in the d-orbital. 1. **Option A: *trans*-Ni(H₂O)₄Cl₂** - Central metal: Ni (Nickel) - Oxidation state and electron configuration need to be determined. 2. **Option B: [Co(CN)₆]³⁻** - Central metal: Co (Cobalt) - Known to form low-spin complexes with strong field ligands like CN⁻. 3. **Option C: *fac*-[FeCl₃Br₃]⁴⁻** - Central metal: Fe (Iron) - Mixed halide ligands wit\( \h getting the specific coordination geometry. 4. **Option D: Δ-[Mn(en)₃]²⁺** - Central metal: Mn (Manganese) - En stands for ethylenediamine, a bidentate ligand that typically forms high-spin complexes. The goal is to identify the complex with a total spin \( \text{S} = 2 \), corresponding to having 4 unpaired electrons. The key is to understand the high-spin or low-spin nature of each complex, given the crystal field splitting and the nature of the ligands. **Graph Explanation:** This problem does not include graphs or diagrams, but a common way to solve such questions involves the use of crystal field splitting diagrams, which visually demonstrate the arrangement of electrons in the high-spin or low-spin states depending on the ligand field strength. By applying the crystal field theory and analyzing the options, one can determine which complex fits the criteria of having 4 unpaired electrons, leading to a spin state \( \text{S} = 2 \). Detailed
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