Which of the following represents the volume of the solid generated by revolving the region bounded by f(x)=(x-1)³ and g(x)=x-1 about the x-axis? ,1 2 A T ¹[(x − 1)² – (x − 1)²]dx − 1 £²[(x − 1)² – (x − 1)º]dx B L'x[0 x[(x-1)-(x-1)³]dx+2n (x − 1) ³]dx af²x[(x-1)³3-(x-1)]dx © 2π 2x 'x[(x-1)³3-(x-1)]dx + 2x *x[(x− 1) – (x− 1) ³]dx 0 1 D TT π ſª[(x − 1)² − (x − 1)º]dx + π ƒ, ª[(x - 1)²-(x - 1)]dx 2n
Which of the following represents the volume of the solid generated by revolving the region bounded by f(x)=(x-1)³ and g(x)=x-1 about the x-axis? ,1 2 A T ¹[(x − 1)² – (x − 1)²]dx − 1 £²[(x − 1)² – (x − 1)º]dx B L'x[0 x[(x-1)-(x-1)³]dx+2n (x − 1) ³]dx af²x[(x-1)³3-(x-1)]dx © 2π 2x 'x[(x-1)³3-(x-1)]dx + 2x *x[(x− 1) – (x− 1) ³]dx 0 1 D TT π ſª[(x − 1)² − (x − 1)º]dx + π ƒ, ª[(x - 1)²-(x - 1)]dx 2n
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Question 3
Which of the following represents the volume of the solid generated by revolving the region bounded by
f(x)=(x-1)³ and g(x)=x-1 about the x-axis?
A
1 [(x - 1) - (x - 1)²]dx - ₁ ² [(x - 1)²-(x - 1)]dx
π
<- T
B
2m
x[(x-1) - (x - 1)³]dx + 2x²x[(x-1)³- (x-1)]dx
© 2n
2x ["'x[(x− 1)³= (x− 1) ]dx + 2x ſªx[(x− 1) — (x− 1) ¹]dx
-
1
1
2
Ⓒ π √ ²[Xx
D
TS" [(x − 1)² = (x − 1)º]dx + ₁ [[(x - 1)²-(x - 1)]dx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72d8f928-2820-443a-ac0b-1665fa6efe5d%2F77fc9aba-a7c1-4fcb-a089-0b6566538b73%2Fd8i6yd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 3
Which of the following represents the volume of the solid generated by revolving the region bounded by
f(x)=(x-1)³ and g(x)=x-1 about the x-axis?
A
1 [(x - 1) - (x - 1)²]dx - ₁ ² [(x - 1)²-(x - 1)]dx
π
<- T
B
2m
x[(x-1) - (x - 1)³]dx + 2x²x[(x-1)³- (x-1)]dx
© 2n
2x ["'x[(x− 1)³= (x− 1) ]dx + 2x ſªx[(x− 1) — (x− 1) ¹]dx
-
1
1
2
Ⓒ π √ ²[Xx
D
TS" [(x − 1)² = (x − 1)º]dx + ₁ [[(x - 1)²-(x - 1)]dx
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