Which of the following options represents the correct syntax to open a file whose name is contained in the variable filename? cout << "Please enter the file name:"; string filename; cin >> filename; ifstream in_file; in_file.open("filename"); in_file.open(c_str(filename)); in_file.open(filename); in_file.open(filename.c_str());

Which of the following options represents the correct syntax to open a file whose name is contained in the variable filename? cout << "Please enter the file name:"; string filename; cin >> filename; ifstream in_file; in_file.open("filename"); in_file.open(c_str(filename)); in_file.open(filename); in_file.open(filename.c_str());

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Linux

An operating system (OS) is the software which manages hardware and resources, like CPU, storage and memory. The OS bridges the applications and hardware and makes the connections between all of your software and the hardware resources.

Question

Which of the following options represents the correct syntax to open a file whose
name is contained in the variable filename?
cout << "Please enter the file name:";
string filename;
cin >> filename;
ifstream in_file;
Oin_file.open("filename");
in_file.open (c_str(filename));
in_file.open (filename);
Oin_file.open(filename.c_str());

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QUESTION 14 [*) filelOtest.cpp #include 2 #include #include #include using namespace std; 3 4 5 6. main() //Declare variables; Step 1 6 ifstream infile; ofstream outFile; double testi, test2, test3, test4, test5; double average; string firstName; string lastName; 10 11 12 13 14 15 16 infile.open("test.txt"); //Step 2 outFile.open("testavg.txt"); //Step 3 outFile > firstName >> 1lastName; //Step 5 outFile > testi >> test2 >> test3>> test4 >> test5; //Step 7 outFile <« "Test scores: " « setw(6) << testi<< setw(6) <« test2 « setw(6) 17 18 19 20 21 22 23 24 25 26 « test3<« setw(6) « test4 « setw(6) <« test5<< endl; //Step 8 27 28 average = (testi + test2 + test3 + test4+ test5) / 5.e; //Step 9 29 30 outFile <« "Average test score: " <« setw(6)<< average << endl; //Step 10 31 infile.close(); //Step 11 outFile.close(); //Step 11 32 33 34 35 return e; 36 37 5 dh Compile Log V Debug Find Results If the file "test.txt" did not exist before you run this program, there will be a syntax error…