Which of the following is the correct null hypothesis for an independent-measures t test? Group of answer choices µ1 – µ2 = 0 M1 – M2 = 0 µ1 – µ2 ≠ 0 M1 – M2 ≠ 0
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- Test the claim that the mean GPA of night students is larger than 2.1 at the 0.01 significance level. The null and alternative hypotheses would be: 0.525 Ho: u = 2.1 Ho: µ = 2.1 Ho:µ = 2.1 Ho:p 0.525 Ho:p 0.525 H:p> 0.525 H1:p+ 2.1 H:µ > 2.1 H:µ < 2.1 H1:p< 0.525 H :p + 0.525 The test is: left-tailed two-tailed right-tailed Based on a sample of 38 people, the sample mean GPA was 2.11 with a standard deviation of 0.2 The p-value is: (to 3 decimals) The significance level is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: Message instructor Submit Question N D archState the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.01 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD The test is: left-tailed right-tailed two-tailed The sample consisted of 45 night students, with a sample mean GPA of 3.23 and a standard deviation of 0.05, and 45 day students, with a sample mean GPA of 3.26 and a standard deviation of 0.08.The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we:
- Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?Plz help asap 46Test the daim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.05 significance level. The null and alternative hypothesis would be: Ho:PN = PD Ho:HN > Hp Ho:PN > PD Ho:HN = HD Ho:HN µp Ha:PN > PD The test is: right-tailed left-tailed two-tailed The sample consisted of 16 night students, with a sample mean GPA of 3.28 and a standard deviation of 0.02, and 14 day students, with a sample mean GPA of 3.3 and a standard deviation of 0.03. test statistic = [three decimal accuracy] p-value = [three decimal accuracy] Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
- Which of the following is the correct null hypothesis for an independent-samples t-test? μ1 – μ2 = 0 x̅1 – x̅2 = 0 μ1 – μ2 ≠ 0 x̅1 – x̅2 ≠ 0For the hypothesis test Ho: 14 against H₁: > 14 with variance unknown and = 11, find the best approximation for the P- value for the test statistic fo = 1.941. O 0.025 sp≤ 0.050 O 0.10 sp≤0.25 O 0.25 sp≤0.50 0.010sp≤ 0.025 O 0.0025sp≤0.0050Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.025 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD The test is: left-tailed two-tailed right-tailed The sample consisted of 35 night students, with a sample mean GPA of 3.34 and a standard deviation of 0.06, and 35 day students, with a sample mean GPA of 3.36 and a standard deviation of 0.03.The test statistic is: _____ (to 2 decimals)The p-value is: ____ (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
- Only 12% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 390 randomly selected registered voters surveyed, 62 of them will vote in the upcoming election. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer > < ≠ = (please enter a decimal) H1:H1: ? p μ Select an answer ≠ < = > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly higher than 12% at αα = 0.01, so…Three students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 418 gram setting. Is there sufficient evidence at the 0.05 level that the bags are underfilled or overfilled? Assume the population is normally distributed. State the null and alternative hypotheses for the above scenario. H0: Ha:
