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- e (ii) (iii) MeO Me. TSN CO₂Et CI CI PCY₁ Ru PCy, Ph benzene, A (cat.) Coz(CO), (cat.) CO, A AD-mix a: K₂OsO₂(OH)4 (cat.) (DHQ)2-PHAL (cat.) K,Fe(CN)6. K₂CO, -BuOH/H₂O, 1:1 TsN Me- MeO OH CO₂Et OHA complexes of the formula [Co(en),CI]CI prepared by the following procedure Dissolve 40 g of CoCl, 6H2O in 125 ml of distilled H,O Dissove 16 g of en in 135 ml of distiled H.O Combine the two solutions Air is farced through the solution for 8 hr. The reaction solution is placed in a targe evaporating dish and 975 ml of conc HCI are added. Concentrate the solution to half of its volume using a steam bath Cool the remaining solution in an ice bath The product collected and washed by suction filtration Calculate the theoretical yield Select one O a 48.0g b. 41.49 O 35 60 Od 38.0 g e 39 69 Nest paeThe coloriesS supe atanliquid was so 11. How does the addition of H3O* affect the following reaction equilibrium? 2CrO42- (aq, yellow) + 2H3O* (aq) -> Cr2O7²- (aq, orange) + 3H2O (1) a. The reaction shifts to the right and the concentration of CrO42- increases. b. The reaction shifts to the right causing the concentration of Cr2072 to decreases and the solution to turns yellow. c. The reaction shifts to the right resulting in a reduction in the concentration of H3O* and an increase in the concentration of Cr2O,2. d. The reaction shifts to the left and the concentration of CrO42 increases. e. The reaction shifts to the left and the concentration of CrO42 decreases.
- 2. In a laboratory experiment you react 20.0 mL of 25% by mass C2H&N2 with 8.000 NiCl2.6H20 to obtain the product Ni(NH2CH2CH½NH2j3Cl2 complex. The C2H3N2 solution used in this experiment is 25.0% by mass, with a density (d) of 0.950 g/mL. (MW NICI2.6H2O= 237.69 g/mole, MW C2HgN2=60.10 g/mole, MW tris(ethylenediamine)nickel(II)chloride = 309.89 g/mole) a. Write down the balanced equation of the synthesis. b. Determine the number of moles of each reactant that you use. c. Determine which reactant is the limiting reactant, giving your reasoning. Show all your work to get full credit. (5 points) d. Calculate your percent yield if the dry product weighs 7.000 g.Predict the product(s) for the following reaction. M9CO (s + heat 3. a. 2. (6 )0ɔ + (s)%o6w Mg0( s) + CO 2. b. Mg( s) + CO ( g) + c. 2. (6,%% Mg 2+(s) + co ( 2 (6)%0 + (6 2' E. No reaction occurs.The solubility constant Ksp of Ag2CrO4 is related to its solubility in water (s) as Ksp
- 1. A sample of feldspar weighing 1.500g is decomposed, and eventually there is obtained a mixture of KCI and NaCi weighing 0.1801 g. These chlorides are dissolved in H20, a 50-mL pipetful of 0.08333 N AGNO3 is added, and the precipitate is filtered off. The filtrate requires 16.47 mL of 0.100ON KCNS, with ferric alum as indicator. Calculate the percentage of K20 in the silicate.Suppose we introduce the following pointdefects.(a) Mg2+ ions substitute for yttrium ionsin Y2O3; (b) Fe3+ ions substitute for magnesiumions in MgO;(c) Li1+ ions substitute for magnesiumions in MgO; and(d) Fe2+ ions replace sodium ions inNaCl.What other changes in each structuremight be necessary to maintain a chargebalance? Explain.6. C3H&M(CO); (M: transition metal) complex obey the 18 electron rules. Draw two possible structure for values of hapticity : 4 and 6, respectively and predict suitable metal atom(s)
- A sample of processed meat scrap weighing 4.000 g is digested with concentrated HSO. and Hg(catalyst) until the N present has been converted to NHHSO.. This is treated with excess NaOH, and the liberated NHs is caught in a 100-ml of H.SO. ( Iml 0.01860 g Na:OJ. The excess acid requires 57.60 ml of NaOH ( ImL = 0.12660 g potassium acid phthalate, KHCaH.OJ. Calculate the percentage protein in the meat scrap 4.Find Ecell = 0.48V. Use dhis regult along with the equilibrium conlentretion of Lu“ (mol/L) wheun 24. C[Cu (NH3), ) = 0.10 mol /L and [N H3] = 6.1 mol/h to calceulate the cqnillibriem Lonstant for the formation of [cu(NH3),]"]According to the valence bond theory, which of the following statements is/are incorrect? (79Au) I- The hybrid type of an outer orbital complex cannot be sp3. II- Square plane compounds are more stable than tetrahedral compounds. In the III- Octahedral, high spin d5 complex, the number of single electrons is 1. IV- Tetrachloroaurate(III) ion is diamagnetic. A. II onlyB. I onlyC.III and IVD. I, II, IVE.I and III