When Y,.Y,.Y, is a random sample from N(u,o), we learned in class that thestatistic T =-Y-uhas t distribution with n-1 degrees of freedom, where Y and S aren-1the sample mean and sample standard deviation, respectively. Write out the form of Tand show algebraically that T can be written as the ratio of two independent xrandomvariables, each divided by their respective degrees of freedom. What is, therefore, thedistribution of T ?,

From the given information, Y1, Y2...Yn is a random sample from Nμ,σ2 T=y¯-μSn-1~tn-1

Answered: When Y,,Y,..Y, is a random sample from…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a large population of adults, the mean IQ is 113 with a standard deviation of 18. Suppose 45 adults are randomly selected for a market research campaign. (Round to 2 decimal places for all z-values and round all other answers to 4 decimal places, if needed.) a) The distribution of IQ is approximately normal ÷ b) The distribution of the sample mean IQ is approximately normal with a mean of and a standard deviation of c) The probability that the sample mean IQ is less than 110 is d) The probability that the sample mean IQ is greater than 110 is e) The probability that the sample mean IQ is between 110 and 117 is
Assume that the amount of weight that male college students gain during their freshman year are normally distributed with a. Mean of u= 1.2 kg and a standard deviation of o= 5.1 kg A. If 1 male college student is randomly selected, Find the probability that he gains between 0 and 3 kg during freshman year B. If 25 male college students are randomly selected find the probability that their mean weight gain during freshman year is between 0 and 3 kg why can the normal distribution be used on pet b even though the sample size does not exceed 30?
The population of college students using “normal shoes” is able to complete a particular racecourse in an average of 250 seconds. The standard deviation for this population is 20 seconds and the population is normally distributed. A random sample of 28 college students is given a special pair of new shoes and asked to run the course. The average “race time” for this group is 243 seconds. assume now that the designer of the shoes states that his shoes should improve the times of the user (less time to finish the race). State the hypotheses involved. determine if the hypothesis test is one tailed or two tailed Give the Z scores associated with cut-off points for .01, .05, and .10 (1%, 5%, and 10% respectively). Calculate the Z score for this problem. Based on a cut-off point or alpha level of .05 (5%), what decision would you make about your hypotheses? Explain this decision. Make conclusions regarding the specifics of this study.
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Let Y, represent the ith normal population with unknown mean #, and unknown variance of for i=1,2. Consider independent random samples, Ya, Ya, Yin, of size n,, from the ith population with sample mean Y, and sample variance S² = (₁-P) ². (d) Define V₁, a function of S1, that has a chi-square distribution. (e) Is V₁ a pivotal function to find a confidence interval for o?? Explain with argument. (f) Find a (1-a) x 100% confidence interval for of
The weights of beagles (dogs) have approximately a normal distribution with u = 17.1 pounds and a standard deviation of o = 1.8 pounds. Suppose that we randomly select n = 64 beagles and measure their weights in pounds. Let X be the random variable representing the mean weight of the selected beagles. Let Xtot be the random variable representing the total weight of the selected beagles. a) About what proportion of beagles have weights between 17 and 18 pounds? b) About what proportion of beagles have weights greater 20 pounds? c) About how many of the 64 sampled beagles have weights less than 16.5 pounds? (nearest integer) d) About how many of the sampled beagles have weights between 17 and 18 pounds? (nearest integer) e) What is the standard deviation of the distribution of X? f) What is the standard deviation of the distribution of Xtot? g) What is the probability that 17 1100? f) Copy your R script for the above into the text box here.
Suppose X is a random variable of uniform distribution between 1 and 7. Find E(X)
If X is a negative binomial rv, then Y= r+Xis the total number of trials necessary to obtainr S’s. Obtain the mgf of Y and then its mean valueand variance. Are the mean and variance intuitively consistent with the expressions for E(X)and V(X)? Explain
5. The distribution of male weight in the United States has a standard deviation of roughly o = 25 lbs. The average weight u varies from state to state. Suppose you randomly select 100 males in Louisiana and ask their weights, and you compute the average weight Xn of the n = 100 males. a) Assuming that the standard deviation of weight in Louisiana is 25 lbs, what does the Central Limit Theorem tell you the (approximate) distribution of X will be?
d,e,f e) This result would be (usual, unusual) so the sample likely came from a population whose mean gestation period is(less, more, equal) to 266 days
The average wait time to get seated at a popular restaurant in the city on a Friday night is 12 minutes. Is the mean wait time greater for men who wear a tie? Wait times for 13 randomly selected men who were wearing a tie are shown below. Assume that the distribution of the population is normal. 13, 13, 11, 13, 13, 13, 13, 10, 12, 13, 13, 10, 13 What can be concluded at the the αα = 0.05 level of significance level of significance? The null and alternative hypotheses would be: H0 = (p,u) (<,>,=,not equal) to _____ H1 = (p,u) (<,>,=,not equal) to _____ The test statistic (t,z) = ___ The p-value = _____ Thus, the final conclusion is that ... The data suggest that the population mean wait time for men who wear a tie is not significantly more than 12 at αα = 0.05, so there is statistically insignificant evidence to conclude that the population mean wait time for men who wear a tie is more than 12. The data suggest the population mean is not significantly more than 12…
The random variable x has a normal distribution with mean 50 and variance 9. Find the value of x, call it x0, such that: a) P(x ≤ xo) = 0.8413 b) P(x > xo) = 0.025 c) P(x > xo) = 0.95 d) P(41 ≤ x ≤ xo) = 0.8630

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