The Bureau of Labor Statistics reported that 16% of U.S. non-farm workers are government employees. A random sample of 65 workers is drawn a) Does the "Central Limit Theorem" hold? Since n. p = . (1 − p) = - n. > 10 we conclude that CLT holds. > 10 and b) The mean of the sample proportion of non-farm workers that are government employees is % and the standard deviation of the sample proportion is op Hp = Round the standard deviation to 3 decimal places. c) The probability that the sample proportion of non-farm workers that are government employees is less than 20% is: P(p < 0.2) = Round your answer to two decimal places. d) What sample proportion is needed for for a non-farm worker to be at the 60th percentile. (HINT: Use inverse probability) P(p < = 0.60. Round your answer to two decimal places.
The Bureau of Labor Statistics reported that 16% of U.S. non-farm workers are government employees. A random sample of 65 workers is drawn a) Does the "Central Limit Theorem" hold? Since n. p = . (1 − p) = - n. > 10 we conclude that CLT holds. > 10 and b) The mean of the sample proportion of non-farm workers that are government employees is % and the standard deviation of the sample proportion is op Hp = Round the standard deviation to 3 decimal places. c) The probability that the sample proportion of non-farm workers that are government employees is less than 20% is: P(p < 0.2) = Round your answer to two decimal places. d) What sample proportion is needed for for a non-farm worker to be at the 60th percentile. (HINT: Use inverse probability) P(p < = 0.60. Round your answer to two decimal places.
MATLAB: An Introduction with Applications
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
Transcribed Image Text:The Bureau of Labor Statistics reported that 16% of U.S. non-farm workers are government employees. A random sample of 65 workers is drawn.
a) Does the "Central Limit Theorem" hold? Since \( n \cdot p = \_\_\_\_\_ \geq 10 \) and \( n \cdot (1 - p) = \_\_\_\_\_ \geq 10 \), we conclude that CLT holds.
b) The mean of the sample proportion of non-farm workers that are government employees is \( \mu_{\hat{p}} = \_\_\_\_\_ \) % and the standard deviation of the sample proportion is \( \sigma_{\hat{p}} = \_\_\_\_\_ \). Round the standard deviation to 3 decimal places.
c) The probability that the sample proportion of non-farm workers that are government employees is less than 20% is: \( P(\hat{p} < 0.2) = \_\_\_\_\_ \). Round your answer to two decimal places.
d) What sample proportion is needed for a non-farm worker to be at the 60th percentile? (HINT: Use inverse probability) \( P(\hat{p} < \_\_\_\_\_) = 0.60 \). Round your answer to two decimal places.
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