When using the exponentially weighted moving average for purposes of smoothing rather than forecasting,
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When using the exponentially weighted moving average for purposes of smoothing rather than forecasting,
use a large weight
the current smoothed value becomes the forecast.
use a small weight.
None of the above.
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Solved in 3 steps
- Construct a scatter plot of the data in the table AND create a linear model. 2 10 12 10 14 14 16 18 18 24 a EGO (99- 2.Simple linear regression model helps to adjust out the effects of confounding factors in a statistical analysis. A. TrueB. FalseC. None of the above choicesAn experiment is run. The mass of an object is recorded over time. Time (min) Mass (g) 32 40 36 32 37 32 39 30 50 27 Using your calculator, run a linear regression to determine the equation of the line of best fit. Round to two decimal places, use x for the variable.y=Using your equation, estimate the mass of the object at 41 minutes.grams=
- A popular television show recently released a video previewing the upcoming season on his website as fans of the show discovered the video the number of views of the preview video has grown each day during the last two weeks the number of days in the release of the video and the natural log of the number of video views as shown in the scatterplot. based on the scatterplot and residual plot, what type of model would be appropriate for summarizing the relationship between days and numbers of views? an exponential model is appropriate because the Residual plot does not show a clear pattern A linear model is appropriate because of scatterplot shows a strong positive linear relationship A power model is appropriate because the scatterplot of days a natural log of use is strong and linear an exponential model is appropriate because the relationship between the days in the natural log of views in linear and the residual plot does not show a clear patternThe data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 352 pounds? Use a significance level of 0.05. Chest size (inches) *Weight (pounds) 44 54 328 528 41 55 39 51 418 580 296 503 Click the icon to view the critical values of the Pearson correlation coefficient r. - What is the regression equation? x (Round to one decimal place as needed.)Jd
- Explain pleasePrehistoric pottery vessels are usually found as sherds (broken pieces) and are carefully reconstructed if enough sherds can be found. An archaeological study provides data relating x = body diameter in centimeters and y = height in centimeters of prehistoric vessels reconstructed from sherds found at a prehistoric site. The following Minitab printout provides an analysis of the data. Predictor Сoef SE Coef T P Constant -0.209 2.429 -0.09 0.929 Diameter 0.7689 0.1471 5.66 0.002 S 4.07980 R-Sq 88.9% %3D For the least-squares line ŷ = a + bx, what is the value of the constant a? What is the value of the slope b? (ote: The slope is the coefficient of the predictor variable.) Write the equation of the least-squares line. a = b = + The P-value for a two-tailed test corresponding to each coefficient is listed under P. The t value corresponding to the coefficient is listed under T. What is the P-value of the slope? Recall that the t value and resulting P-value of the slope b equal thet value…Prehistoric pottery vessels are usually found as sherds (broken pieces) and are carefully reconstructed if enough sherds can be found. Information taken from a study provides data relating x = body diameter in centimeters and y = height in centimeters of prehistoric vessels reconstructed from sherds found at a prehistoric site. The following Minitab printout provides an analysis of the data. Predictor Coef SE Coef T P Constant -0.233 2.429 -0.09 0.929 Diameter 0.7948 0.1671 5.33 0.001 S = 4.10980 R-Sq = 80.3% (a) The standard error Se of the linear regression model is given in the printout as "S." What is the value of Se? (b) The standard error of the coefficient of the predictor variable is found under "SE Coef." Recall that the standard error for b is Se Σx2 − 1 n (Σx)2 . From the Minitab display, what is the value of the standard error for the slope b?
- Ocean currents are important in studies of climate change, as well as ecology studies of dispersal of plankton. Drift bottles are used to study ocean currents in the Pacific near Hawaii, the Solomon Islands, New Guinea, and other islands. Let x represent the number of days to recovery of a drift bottle after release and y represent The distance from point of release to point of recovery in km/100. The following data a representative of one study using drift bottles to study ocean currents. x day 72 79 32 96 203 y km/100 14.8 19.6 5.3 11.8 35.1 Σx=482 Σy=86.6 Σx2=62874 Σy2=2002.54 Σxy=11041.7 r=.93787 use a 1% level of significance to test the claim p>0.(use 2 decimal places) t=critical t= Se=4.4913 a=1.4966 b=.1641 D) find the predicted distance (km/100) when a drift bottle has been floating for 80 days.(use 2 decimal places) find a 90% confidence interval for your prediction of part D. (use 2 decimal places) lower limit=___km/100upper limit=___km/100 he was a 1% level of…The plot below is a residual plot (residuals versus x) of residuals remaining after fitting a linear model to a set of data. Describe important features and determine if a linear model would be appropriate for this data set. Choose all answers that apply. A linear model would NOT be appropriate A linear model would be appropriate There is higher variability with smaller x There is higher variability with larger xM3
