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When the reaction below reaches equilibrium, does the equilibrium lie on the left or the right side? Briefly explain. CIO- + CH,CO,H = HCIO + CH,Co,"

When the reaction below reaches equilibrium, does the equilibrium lie on the left or the right side? Briefly explain. CIO- + CH,CO,H = HCIO + CH,Co,"

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. a. When the reaction below reaches equilibrium, does the equilibrium lie on the left or the right side? Briefly explain. clo + CH,CO,H HClO + CH,CO,
Transcribed Image Text:2. a. When the reaction below reaches equilibrium, does the equilibrium lie on the left or the right side? Briefly explain. clo + CH,CO,H HClO + CH,CO,
R= 0.08205 L atm/K mol = 8.314 x 10 kJ/K mol K, for HNO, = 4.0 x 104 к, for HOCI 1.2 х 10 К, for CH,COOH 1.8 х 10> K, for H,S = 1.0x 10 K, for H,S = 1.0 x 1014 K, for Pbs = 7.0 x 10- Kp for NiS = 3.0 x 10 For H,S K, = 1.0 x 10", K, = 1.0 x 10-", (H,S) in a saturated solution = 0.10 M For H,PO, K, - 7.5 х 10, к, - 6.2 х 10*, к, 4.8 х 1о 1 Average Bond Energies (kJ/mol): H-H 432, C-H 413, C-C 347
Transcribed Image Text:R= 0.08205 L atm/K mol = 8.314 x 10 kJ/K mol K, for HNO, = 4.0 x 104 к, for HOCI 1.2 х 10 К, for CH,COOH 1.8 х 10> K, for H,S = 1.0x 10 K, for H,S = 1.0 x 1014 K, for Pbs = 7.0 x 10- Kp for NiS = 3.0 x 10 For H,S K, = 1.0 x 10", K, = 1.0 x 10-", (H,S) in a saturated solution = 0.10 M For H,PO, K, - 7.5 х 10, к, - 6.2 х 10*, к, 4.8 х 1о 1 Average Bond Energies (kJ/mol): H-H 432, C-H 413, C-C 347
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