When the Pb²+ concentration is 1.02 M, the observed cell potential at 298 K for an cell with the following reaction is 0.736 V. What is the electrochemical Zn²+ concentration? Pb²+ (aq) + Zn(s) → Pb(s) + Zn²+ (aq) Pb2+ (aq) + 2e → Pb(s) Eed -0.126 V Zn²+ (aq) + 2e → Zn(s) Ee -0.763 V red Answer: M When the Pb2+ concentration is 7.36x10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.519V. What is the Cr³+ concentration? = 3Pb²+ (aq) + 2Cr(s) 3Pb(s) + 2Cr³+ (aq) M
When the Pb²+ concentration is 1.02 M, the observed cell potential at 298 K for an cell with the following reaction is 0.736 V. What is the electrochemical Zn²+ concentration? Pb²+ (aq) + Zn(s) → Pb(s) + Zn²+ (aq) Pb2+ (aq) + 2e → Pb(s) Eed -0.126 V Zn²+ (aq) + 2e → Zn(s) Ee -0.763 V red Answer: M When the Pb2+ concentration is 7.36x10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.519V. What is the Cr³+ concentration? = 3Pb²+ (aq) + 2Cr(s) 3Pb(s) + 2Cr³+ (aq) M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Question
![When the
Pb²+ concentration is 1.02 M, the observed cell potential at 298 K for an
cell with the following reaction is 0.736 V. What is the
electrochemical
Zn²+ concentration?
Pb²+ (aq) + Zn(s) → Pb(s) + Zn²+ (aq)
Pb²+ (aq) + 2e →→ Pb(s) Eed
Zn²+ (aq) + 2e
Answer:
M
= -0.126 V
→ Zn(s) Ered -0.763 V
When the Pb2+ concentration is 7.36x10-4 M, the observed cell potential at 298K for
an electrochemical cell with the following reaction is 0.519V. What is the Cr³+
concentration?
M
=
3Pb²+ (aq) + 2Cr(s)-3Pb(s) + 2Cr³+ (aq)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6057cc0e-0794-4d8b-a8a7-d99e436e287b%2Fca0ddd53-5835-4627-bf9f-5af6e4f6c81a%2Fz30fsb7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When the
Pb²+ concentration is 1.02 M, the observed cell potential at 298 K for an
cell with the following reaction is 0.736 V. What is the
electrochemical
Zn²+ concentration?
Pb²+ (aq) + Zn(s) → Pb(s) + Zn²+ (aq)
Pb²+ (aq) + 2e →→ Pb(s) Eed
Zn²+ (aq) + 2e
Answer:
M
= -0.126 V
→ Zn(s) Ered -0.763 V
When the Pb2+ concentration is 7.36x10-4 M, the observed cell potential at 298K for
an electrochemical cell with the following reaction is 0.519V. What is the Cr³+
concentration?
M
=
3Pb²+ (aq) + 2Cr(s)-3Pb(s) + 2Cr³+ (aq)
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