When the Pb²+ concentration is 2.45x10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is0.507V. What is the Cr³+ concentration?3Pb²+ (aq) + 2Cr(s)—3Pb(s) + 2Cr³+ (aq)Answer: 1.62Use the References to access important values if needed for this question.M When thePb²+concentration is 1.14 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 1.154 V. What istheMn²+ concentration?Pb²+ (aq) + Mn(s) → Pb(s) + Mn²+redPb²+ (aq) + 2e¯ → Pb(s) EeMn²+ (aq) + 2e¯¯ → Mn(s) Fred[Mn²+] =0M(aq)= -0.126 V-1.180 V

Standard cell emf: It is the maximum electrode potential difference between the two electrodes in…

When the Pb²+ concentration is 2.45×104 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.507V. What is the Cr³+ concentration? 3Pb²+ (aq) + 2Cr(s)—3Pb(s) + 2Cr³+ (aq) Answer: 1.62 M

When the Pb²+ concentration is 2.45×104 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.507V. What is the Cr³+ concentration? 3Pb²+ (aq) + 2Cr(s)—3Pb(s) + 2Cr³+ (aq) Answer: 1.62 M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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