When the Pb²+ concentration is 1.49×104 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.501V. What is the Cr³+ concentration? 3Pb²+(aq) + 2Cr(s)3Pb(s) + 2Cr³+ (aq) Answer: I M

When the Pb²+ concentration is 1.49×104 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.501V. What is the Cr³+ concentration? 3Pb²+(aq) + 2Cr(s)3Pb(s) + 2Cr³+ (aq) Answer: I M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

When the Pb²+ concentration is 1.49x104 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.501V. What is the Cr³+
concentration?
3Pb²+ (aq) + 2Cr(s)- →3Pb(s) + 2Cr³+ (aq)
Answer: I
M

When the Pb²+ concentration is 5.35x10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.437V. What is the Al³+
concentration?
3Pb²+ (aq) + 2Al(s)- →3Pb(s) +
Answer:
-2A1³+ (aq)
M

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Step 1: Determine the concentration of chromium ion from the given data:

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Step 3: (ii) Calculation for concentration of aluminum ion:

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