When the Pb²+ concentration is 1.05 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 2.343 V. What is the Mg2+ concentration? Pb2+ (aq) + Mg(s)→ Pb(s) + Mg2+ (aq) -0.126 V red Pb2+ (aq) + 2e → Pb(s) E Mg2+ (aq) + 2e → Mg(s) = -2.370 V red [Mg]-C Submit Answer Use the References to access important values if needed for this question. M nererende Retry Entire Group 9 more group attempts remaining
When the Pb²+ concentration is 1.05 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 2.343 V. What is the Mg2+ concentration? Pb2+ (aq) + Mg(s)→ Pb(s) + Mg2+ (aq) -0.126 V red Pb2+ (aq) + 2e → Pb(s) E Mg2+ (aq) + 2e → Mg(s) = -2.370 V red [Mg]-C Submit Answer Use the References to access important values if needed for this question. M nererende Retry Entire Group 9 more group attempts remaining
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![When the
Pb2+ concentration is 1.05 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 2.343 V.
What is the
Mg2+ concentration?
#
3
[Mg2+]
E
D
Pb²+ (aq) + Mg(s) → Pb(s) + Mg2+ (aq)
= -0.126 V
Pb2+ (aq) + 2e → Pb(s) E red
Mg2+ (aq) + 2e → Mg(s) = -2.370 V
red
Submit Answer
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M
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Transcribed Image Text:When the
Pb2+ concentration is 1.05 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 2.343 V.
What is the
Mg2+ concentration?
#
3
[Mg2+]
E
D
Pb²+ (aq) + Mg(s) → Pb(s) + Mg2+ (aq)
= -0.126 V
Pb2+ (aq) + 2e → Pb(s) E red
Mg2+ (aq) + 2e → Mg(s) = -2.370 V
red
Submit Answer
$
4
R
FL
M
Use the References to access important values if needed for this question.
Retry Entire Group 9 more group attempts remaining
%
5
Cengage Learning Cengage Technical Support
T
G
MacBook Pro
^
6
C
Y
&
7
H
U
N
* 00
8
J
1
(
9
M
(
K
e
O
)
O
*
L
<
.
A
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