When the Pb²+ concentration is 1.05 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 2.343 V. What is the Mg2+ concentration? Pb2+ (aq) + Mg(s)→ Pb(s) + Mg2+ (aq) -0.126 V red Pb2+ (aq) + 2e → Pb(s) E Mg2+ (aq) + 2e → Mg(s) = -2.370 V red [Mg]-C Submit Answer Use the References to access important values if needed for this question. M nererende Retry Entire Group 9 more group attempts remaining

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When the
Pb2+ concentration is 1.05 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 2.343 V.
What is the
Mg2+ concentration?
#
3
[Mg2+]
E
D
Pb²+ (aq) + Mg(s) → Pb(s) + Mg2+ (aq)
= -0.126 V
Pb2+ (aq) + 2e → Pb(s) E red
Mg2+ (aq) + 2e → Mg(s) = -2.370 V
red
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Transcribed Image Text:When the Pb2+ concentration is 1.05 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 2.343 V. What is the Mg2+ concentration? # 3 [Mg2+] E D Pb²+ (aq) + Mg(s) → Pb(s) + Mg2+ (aq) = -0.126 V Pb2+ (aq) + 2e → Pb(s) E red Mg2+ (aq) + 2e → Mg(s) = -2.370 V red Submit Answer $ 4 R FL M Use the References to access important values if needed for this question. Retry Entire Group 9 more group attempts remaining % 5 Cengage Learning Cengage Technical Support T G MacBook Pro ^ 6 C Y & 7 H U N * 00 8 J 1 ( 9 M ( K e O ) O * L < . A Email Instructor I Previous P V Next> Save and Exit + 11 = 11 ? 2
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