Answered: When r >> d, the electric field… | bartleby

Related questions

Question

When r >> d, the electric field strength at the dot is
+Q +
d
+2Q
+ Õ+
4TEor2
4Q
4meo (72+d²)
4Q
4Q
4TEO72
2Q
x)

Expert Solution

Step 1

According to Coulomb's law the electric field at a point in space due to a charge is given by,

$E = \frac{1}{4 π ε_{0}} \frac{q}{l^{2}} (1) w h e r e l = \sqrt{r^{2} + d^{2}}$

When $r ≫ d$ ,

$r^{2} + d^{2} \approx r^{2} (2)$

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

An electron is shot directly toward the center of a large metal plate that has surface charge density −2.50 ✕ 10−6 C/m2. If the initial kinetic energy of the electron is 1.50 ✕ 10−16 J and if the electron is to stop (owing to electrostatic repulsion from the plate) just as it reaches the plate, how far from the plate must the launch point be? ____________m
The cell membrane in a nerve cell has a thickness of 0.12 µm. Approximating the cell membrane as a parallel-plate capacitor with a surface charge density of 5.9 x 10-6C/m², find the electric field within the membrane.
10:58 LTE 5 e + A •.. (8) Two charges are shown. What is the direction of the electric field at the indicated point?(WHY?) +2 μC. A + C D E . 1 μC A) A В) В С) С D) D E) E В I U A Ok Hi Q wER TYU0P ASDFGHJK L z x c v B N M 123 space return
Which expression gives the correct electric field magnitude at point P for the geometry shown in the figure? 1 2g 4περ r 1 E = b- 2 E = v2; 2q 4T€0 r2 1 r , 4 50% || b- 2 1 E = /2; 4T€0 r2 CORRECT V2 _1 2 4T€0 E = 50% P.
15 20 10 + →15 15 Field strengths in N/C 20 Each electric field is constant over each face of the box. The box contains Positive charge. O Negative charge. O No net charge. O Not enough information to tell.
A very long insulating cylindrical shell of radius 6.70 cm cames charge of linear density 8.70 μC/m spread uniformly over its outer surface. You may want to review (Pages 765-769) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An infinite line charge or charged conducting cylinder What would a voltmeter read if it were connected between the surface of the cylinder and a point 4.80 cm above the surface? 195] ΑΣΦ AV= Submit Request Answer Part B AV- What would a voltmeter read if it were connected between the surface and a point 1.00 cm from the central axis of the cylinder? 1Η ΑΣΦΑ Submit ? Request Answer V ? V
A spherical capacitor is composed of two concentric conducting spheres, one of radius a and the other of radius c (c > a). In addition, between the two conductors there is a spherical shell of dielectric material (relative permittivity/relative dielectric constant ) with inner radius b (c > b > a) and outer radius c. The charge on the inner conductor is +Q. The charge on the outer conductor is -Q. (a) Make a sketch of the situation, indicating the relevant dimensions. (b) Determine the magnitude of the electric field E at radius r for a < r < b. (c) Determine the magnitude of the electric field E at radius r for b < r < c. (d) What is the (induced) surface charge density on the inner surface of the dielectric. (e) Sketch the radial component of the electric field versus r . (f) Sketch the electrostatic potential versus r . (g)Calculate the potential difference between the conductor at r = a and that at r = c. (h) What is the capacitance of this capacitor?
I need help for these questions, I am studying for the physics exam and I couldn't solve this questions which are in the study plan of physics-102. Thanks in advance.